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4 years ago

How do I solve this?

Mathematics

2 answers:

Ivanshal [37]4 years ago

3 0

To solve for x you have to get x by itself. multiply both sides by 6. this will leave you with 12 = x

laila [671]4 years ago

3 0

You would want to multiply across so multiply the 2 with the 6 and you would have your answer

X=12

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Solve triangles using the law of cosines Find m angleB. Round to the nearest degree,

andrey2020 [161]

Answer:

Step-by-step explanation:

CosB = ((15^2) + (8^2) - (14^2)) / (-2(15)(8))

cosB = 93 / -240

Take inverse cosine:

113°

5 0

3 years ago

Rewrite 4/6:1/3 as a unit rate. A: 2/1 B: 12/6 C: 2/9 D: 12/1

polet [3.4K]

Answer:

2/1

Step-by-step explanation:

get the first part of each fraction to something divisible by the second part

4 · 3= 12/6

1 · 3= 3/3

12÷2= 2 3÷3= 1

2/1

4 0

3 years ago

A rectangle has the length of 22 inches less than 7 times the width. If the area of the rectangle is 3197 square inches, find th

Nikolay [14]

The length of rectangle is 139 inches

Solution:

Given that, area of the rectangle is 3197 square inches

Let "L" be the length of rectangle and "W" be the width of rectangle

Also given that rectangle has the length of 22 inches less than 7 times the width

Length = 7 times width - 22

L = 7W - 22

The area of rectangle is given as:

$\text {Area of rectangle }=\text { length } \times \text { width }$

Substituting the values we get,

$\begin{array}{l}{3197=(7 W-22)(W)} \\\\ {3197=7 W^{2}-22 W} \\\\ {7 W^{2}-22 W-3197=0}\end{array}$

On solving the above quadratic equation using quadratic formula,

$\text {For the quadratic equation } a x^{2}+b x+c=0 \text { where } a \neq 0$

$x=\frac{-b \pm \sqrt{\left(b^{2}-4 a c\right)}}{2 a}$

$\begin{array}{l}{\text {Here in } 7 \mathrm{W}^{2}-22 \mathrm{W}-3197=0} \\\\ {a=7 ; b=-22 ; c=-3197}\end{array}$

Substituting in above quadratic formula,

$\begin{array}{l}{W=\frac{-(-22) \pm \sqrt{\left((-22)^{2}-4(7)(-3197)\right)}}{2 \times 7}} \\\\ {W=\frac{22 \pm \sqrt{90000}}{14}=\frac{22 \pm 300}{14}} \\\\ {W=\frac{22+300}{14} \text { or } W=\frac{22-300}{14}} \\\\ {W=23 \text { or } W=-19.85}\end{array}$

Since width of rectangle cannot be negative, ignore negative value of "W"

So width W = 23 inches

Length L = 7W - 22 = 7(23) - 22 = 139 inches

Thus length of rectangle is 139 inches

8 0

4 years ago

If you roll two number cubes, what is the probability of their sum being equal to a value of seven or higher?

rodikova [14]

If the cubes are die such that each face has numbers from 1 to 6. Rolling two of them, there are 6x6 or 36 ways in which they may be arranged. For their numbers to sum to 7, the numbers should be 1 and 6, 2 and 5, 2 and 6, 3 and 4, 3 and 5, 3 and 6, 4 and 3, 4 and 4, 4 and 5, 4 and 6, 5 and 2, 5 and 3, 5 and 4, 5 and 5, 5 and 6, 6 and 1, 6 and 2, 6 and 3, 6 and 4, 6 and 5, 6 and 6. All in all there are 21 out of 36 and the probability is equal to 7/12.

3 0

3 years ago

Read 2 more answers

Write an equation of the line passing through (-6, 1) that is perpendicular to the line 2x -5y = 2

Bess [88]

Answer:

y= -5/2 x + 14 (point slope form)

2y+5x=28 (standard form)

Step-by-step explanation:

Perpendicular lines met the following condition

m1*m2=-1 (the product of their slopes is -1)

To obtain m2, the slope of our desired line lets first re arrange the equation of the first line. 2x-5y=2, so. 2x-2=5y.

Isolating y, leads the following, result: y= 2/5 x - 2/5

m1=2/5

m2 is =-5/2

The equation of our desired line is the following

y=mx+b, we have m, which is -5/2, but still need to find value for b.

Lets now evaluate the above equation in the given point (-6,1).

1=-6 * -5/2 + b.

b=14.

Now we can say the equation that our desired line is

y= -5/2 x + 14 (point slope form)

Or... If we group variables 'x' and 'y' together

y+5/2 x = 14, we want integer coefficients, so lets multiply this expression by 2, to obtain the following:

2y+5x=28

4 0

3 years ago