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Vitek1552 [10]
3 years ago
5

Write the standard equation of the circle with center (-8, -7) and a radius of 6.

Mathematics
2 answers:
weqwewe [10]3 years ago
5 0
Standard form:
(x - h)^2 + (y - k)^2 = r^2
(h, k) is the center and r is the radius
(x - - 8)^2 + (y - - 7)^2 = 6^2
(x + 8)^2 + (y + 7)^2 = 36
hichkok12 [17]3 years ago
3 0
\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&-8&-7&6
\end{array}
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A board measures 4 yards, 2 feet, and 6 inches. What is its length in feet?
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The diagram shows a regular hexagon and a regular pentagon.
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Since a regular polygon has equal interior angles, then the measure of the angle marked x is: 132°.

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Y=2x-4 <br> What is the five ordered pairs and completing the input/output table
kati45 [8]

Answer:

{(0, -4), (1, -2), (2, 0), (3, 2), (4, 4)}

<u>Input values (x)</u> = {0, 1, 2, 3, 4}

<u>Output values (y)</u> = {-4, -2, 0, 2, 4}

Step-by-step explanation:

Given the linear equation, y = 2x - 4, you could practically choose any input value (for x), to have an output value (for y).

If x = 0:

y = 2(0) - 4

y = 0 - 4

y = -4

First ordered pair: y-intercept =  (0, -4)

If x = 1:

y = 2(1) - 4

y= 2 - 4

y = -2

Second ordered pair: (1, -2).

If x = 2:

y = 2(2) - 4

y= 4 - 4

y = 0

Third ordered pair: x-intercept =  (2, 0).

If x = 3:

y = 2(3) - 4

y = 6 - 4

y = 2

Fourth ordered pair: (3, 2).

If x = 4:

y = 2(4) - 4

y = 8 - 4

y = 4

Fifth ordered pair: (4, 4).

Your input values (x) = {0, 1, 2, 3, 4}

Your output values (y) = {-4, -2, 0, 2, 4}

6 0
2 years ago
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