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Vitek1552 [10]
3 years ago
5

Write the standard equation of the circle with center (-8, -7) and a radius of 6.

Mathematics
2 answers:
weqwewe [10]3 years ago
5 0
Standard form:
(x - h)^2 + (y - k)^2 = r^2
(h, k) is the center and r is the radius
(x - - 8)^2 + (y - - 7)^2 = 6^2
(x + 8)^2 + (y + 7)^2 = 36
hichkok12 [17]3 years ago
3 0
\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&-8&-7&6
\end{array}
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For what value(s) of k will the relation not be a function?
kolbaska11 [484]

Answer:

  • See below

Step-by-step explanation:

The relation is not a function when x -value is same but y- values are different.

#1

  • k^2 = 4k
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#2

  • k^2 - 5k = k + 7
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#3

  • k^3 - 5k^2 + 3k = -k
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#4

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8 0
3 years ago
I NEED HELP WITH THIS! ANYONE???
Aneli [31]

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Step-by-step explanation:

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3 years ago
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3 years ago
Ken’s predicted temperature for April is 7ºC. His prediction for May is 2ºC higher than April. He used the number line to solve
Gekata [30.6K]

Answer:

He should have moved to the right.

Step-by-step explanation:

Ken moved 7 to the right which is correct because he needs to get 7º higher, but when he moved 2º to the left that would be a temperature decrease which is is incorrect.

7 0
3 years ago
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The point (6, 7) is reflected across the y axis. what are the coordinates of the reflection
aev [14]

Answer:

Hello!!

the point (6, 7) is reflected across the y axis. what are the coordinates of the reflection?

(-6, 7)

Step by Step Explanation:

When reflecting (x, y) over the x axis is (x, -y)

When reflecting (x, y) over the y axis is (-x, y)

Hope this helps!

7 0
2 years ago
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