Answer:
we have that z = 1.8326 which is not close to z factor of 0. The result is not within limits.
Step-by-step explanation:
Following normal approximation to binomial we have
mean = n×p
standard deviation = √(n×p×(1-p))
n is equal to 160
p is equal to 35%
n×p is equal to 150×0.35 = 52.5
this is the probability that you would expect based on the knowledge that 35% of survey respondents said they would prefer a boy than a girl.
in your survey you got 74 out of 150 and you want to know if this is statistically significant or if you can expect this deviation by chance.
standard deviation is calculated as √(n×p× (1-p))which becomes
√ (150×0.35×0.75 = 6.2749 which is more than enough accuracy for what is required.
without a continuity correction, your formula would be:
z (74 > 52.5) = (population mean - sample mean) / population standard deviation which becomes (74-52.5)/6.2749 = 1.8326
this is not close to a z factor of 0 which means that the results are not within limits.
with a continuity correction, your formula would be:
z (52.5 > 52.5) = 0
A z factor of zero means that your sample mean is exactly the population mean.
