Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
Answer:
5 seed packets
Step-by-step explanation:
65 divided by 13 is 5
Answer:
b. (-5, 4)
Step-by-step explanation:
edge2020
Answer:
A. 4x^2 - 9
Step-by-step explanation:
2x * 2x = <u>4x^2</u>
2x * -3 = <u>-6x</u>
3 * 2x = 6x
-3 * 3 = -9
-6x + 6x = 0, so we're left with 4x^2 - 9
Answer:
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