Answer:
65.3658 inches
Step-by-step explanation:
Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value
such that
, but,
, i.e.,
is the 76th percentile of the standard normal distribution. So,
,
. Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.
I believe it would be 0 fr
For points (x1,y1) and (x2,y2)
slope=(y1-y2)/(x1-x2)
(-4,-13)
(19,11)
x1=-4
y1=-13
x2=19
y2=11
slope=(-13-11)/(-4-19)=-24/-23=24/23
B is answer
Answer:
the square root of 50 and 60
Step-by-step explanation: