3a. Write an equation in slope-intercept form of a line that passes through (2,1) and (6,-5).

Mathematics

1 answer:

eimsori [14]2 years ago

5 0

Answer:

$y =- 3/2x + 4$

Step-by-step explanation:

$(2,1) and (6,-5).\\x_1 = 2\\x_2 = 6\\y_1 =1\\y_2 =-5\\\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\\ \\\frac{y-1}{x-2} = \frac{-5-1}{6-2}\\\\\frac{y-1}{x-2} = \frac{-6}{4} \\Cross-Multiply\\4(y-1) = -6(x-2)\\4y-4=-6x+12\\4y =-6x+12+4\\4y = -6x+16\\Divide- through-by ; 4\\\frac{4y = -6x+16}{4} \\\\y = -\frac{3}{2} x +4$

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