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tamaranim1 [39]
3 years ago
15

Please help me out please

Mathematics
2 answers:
Doss [256]3 years ago
5 0
Aye do you know the answer to this or have you gotten to this part yet

SOVA2 [1]3 years ago
4 0

Answer:

16.6 in

Step-by-step explanation:

The volume (V) of a pyramid is

V = \frac{1}{3} area of base × h

where h is the perpendicular height and area of base = 14² = 196

here V = 980, so

\frac{1}{3} × 196h = 980 ( multiply both sides by 3 )

196h = 2940 ( divide both sides by 196 )

h = 15

Consider the right triangle formed by the height h from the vertex to the midpoint of the base and the slant height (s) ← the hypotenuse

Using Pythagoras' identity in the right triangle

s² = 15² + 7² = 225 + 49 = 274 ( take the square root of both sides )

s = \sqrt{274} ≈ 16.6

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rjkz [21]

Answer: x= \frac{1}{5} Makes It True

Explantion: step 1: simplify both sides of the equation. −5x−(−7−4x)=−2(3x−4) −5x+−1(−7−4x)=−2(3x−4)(distribute the negative sign) −5x+(−1)(−7)+−1(−4x)=−2(3x−4) −5x+7+4x=−2(3x−4) −5x+7+4x=(−2)(3x)+(−2)(−4)(distribute) −5x+7+4x=−6x+8 (−5x+4x)+(7)=−6x+8(combine like terms) −x+7=−6x+8 −x+7=−6x+8 step 2: add 6x to both sides. −x+7+6x=−6x+8+6x 5x+7=8 step 3: subtract 7 from both sides. 5x+7−7=8−7 5x=1

If I Helped, Please Mark Me As Brainliest, Have A Great Day :D

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10. 10. If AB bisects CAF, and m&lt;EAF = 72°,<br>then the m&lt;BAF =​
never [62]

The measure of ∠BAF is 54°.

Solution:

DF and CE are intersecting lines.

m∠EAF = 72° and AB bisects ∠CAF.

∠EAF and ∠DAC are vertically opposite angles.

Vertical angle theorem:

<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>

∠DAC ≅ ∠EAF

m∠DAC = 72°

<em>Sum of the adjacent angles in a straight line = 180°</em>

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m∠DAE + 72° = 180°

Subtract 72° from both sides.

m∠DAE = 108°

∠CAF and ∠DAE are vertically opposite angles.

⇒ m∠CAF = m∠DAE

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m∠CAB + m∠BAF = 108°

m∠BAF + m∠BAF = 108°

2 m∠BAF = 108°

Divide by 2 on both sides, we get

m∠BAF = 54°

Hence the measure of ∠BAF is 54°.

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