All categories

2 years ago

I need help !! Can someone answer this mathematics question for algebra 1. Question number five pls.

Mathematics

1 answer:

Ymorist [56]2 years ago

7 0

Answer:

3x cubed- 3x squared- 11x -22

You might be interested in

SOMEONE PLZ HELP ME DO THIS???

Lelu [443]

First do 48.50-21 then divide that amount by 5. Then that’s how much each pair of socks cost so
48.50-21=27.50
27.50%5=$5.50 so rx=$5.50

7 0

3 years ago

Read 2 more answers

Your beginning balance on your lunch account is $55. You buy lunch for 1.75 everyday and sometimes buy a snack for $0.85 after 2

Agata [3.3K]

Multiply 1.75 with 25 because you bought snacks everyday and then you’re left with 11.25

Now subtract .20 because you were left with that on day 26 and you get 11.05

Lastly you divide 11.05 with .85 to see how many snacks you bought

ANSWER IS 13 snacks

3 0

3 years ago

The Midpoint of GH is M(4,-3). One endpoint is G(-2,2). Find the coordinates of endpoint H.

77julia77 [94]

Answer:

Step-by-step explanation:

(x - 2)/2 = 4

x - 2 = 8

x = 10

(y + 2)/2 = -3

y + 2 = -6

y = -8

(10, -8)

3 0

3 years ago

How many solutions does the following equation have? 3(4x+3)=3+12x

TiliK225 [7]

3(4x+3)=3+12x

12x+9=3+12x

9=3

0 solutions

3 0

3 years ago

What's the volume? I honestly just need the formula.

Arturiano [62]

Answer:

$v=364.5\ m^3$

Step-by-step explanation:

Volume Of A Regular Solid

When a solid has a constant cross-section, the volume can be found by multiplying the area of the base by the height. The area of a trapezium is

$\displaystyle A_t=\frac{b_1+b_2}{2}h$

where $b_1$ and $b_2$ are the lengths of the parallel sides and h the distance between them.

The figure shows a solid with a trapezoid as the constant cross-section and a height x. The volume of the solid is

$\displaystyle v=A_t\ x$

$\displaystyle v=\frac{b_1+b_2}{2}\ h\ x$

The image doesn't explicitly say if the length of 4.5 is the height of the trapezium or the length of that side. We'll assume the first, so our data is:

$\displaystyle b_1=7m,\ b_2=11m,\ h=4.5m,\ x=9m$

We now compute the volume

$\displaystyle v=\frac{7+11}{2}.(4.5)(9)=364.5$

$\boxed{\displaystyle v=364.5\ m^3}$

8 0

3 years ago