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grin007 [14]
3 years ago
7

PLEASE HELP NOW --- >N is a 2-digit even number. If the last two digits of N^2 is the same as N, what is the sum of digits of

N?
Mathematics
1 answer:
taurus [48]3 years ago
6 0

Answer:

76.

Step-by-step explanation:

It is given that N is a 2-digit number.

Last two digits of N^2 is the same as N.

We know that, a number is even if it ends with 0,2,4,6,8.

2^2=4,4^2=16,6^2=36,8^2=64

If 0 is in end then we get two zeros in the square of that number.

It is clear that, number should ends with 6 to get the same number at the end.

16^2=256

26^2=676

36^2=1296

46^2=2116

56^2=3136

66^2=4356

76^2=5776

86^2=7396

96^2=9216

It is clear that last two digits of (76)^2 is the same as 76.

Therefore, the required number is 76.

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<u>Explanation:</u>

We need to think of this in terms of right triangles.  If Wendy is 60 feet from a tree, the base of the right triangle is 60 feet.  The height of the tree is the height of the right triangle.  The angle of elevation is the one from the ground at her feet to the top of the tree and then to the bird.  Let's start with the top of the tree first.

She's 60 feet away, we have the angle of elevation as 25 degrees, and we are looking for the height of the tree.  In regards to the angle, the base of 60 is adjacent, and the height of the tree is opposite.  The tangent ratio is height / base.

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Step-by-step explanation:

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