Answer:
<h2>3</h2>
Step-by-step explanation:
IF point E lies on the line segment DF, this means that all the points DEF are collinear and DE+EF = DF.
Given parameter
DE = 6
DF = 9
Required
EF
Substituting the given parameter into the expression above to get the required will be;
DE+EF = DF.
EF = DF-DE
EF = 9-6
EF = 3
Hence the length of EF is equivalent to 3
It is 32 because highest number subtracted by lowest
Answer:
The one with arrows are the answers
->Line segment E B is bisected by Line segment D F .
->A is the midpoint of Line segment F C .
Line segment F C bisects Line segment D B.
->Line segment E B is a segment bisector.
->FA = One-halfFC.
Line segment D A is congruent to Line segment A B .
Step-by-step explanation:
I did it on edge and got it right
Answer:
Step-by-step explanation:
band alone 11
choir alone 17
band and choir alone 4
band and math alone 7
math and choir alone 6
band choir and math 3
math alone 9 from 11+4+10+6+17 + M = 57
so
2 classes = 4+7+6 = 17
17 students take exactly two classes with Mr. Green
Answer:
Step-by-step explanation:
Since the length of both legs of the right angle triangle are given, we would determine the hypotenuse, h by applying Pythagoras theorem which is expressed as
Hypotenuse² = one leg² + other leg²
Therefore,
h² = (3a)³ + (4a)³
h² = 27a³ + 64a³
h² = 91a³
Taking square root of both sides,
h = √91a³
The formula for determining the perimeter of a triangle is expressed as
Perimeter = a + b + c
a, b and c are the side length of the triangle. Therefore, the expression for the perimeter of the right angle triangle is
√91a³ + (3a)³ + (4a)³
= √91a³ + 91a³
