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kumpel [21]
3 years ago
11

How can i find values if h(-4) h(x)=1/2x-1???

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

plug in -4 in for x. then solve.

h(-4)=1/2(-4)-1

h(-4)= -3

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Lemur [1.5K]

The minimum number of shirt they will sell to make the given profit is 192 shirts

<h3>Inequality expression</h3>

Inequalities are equations not separated by an equal sign.

If a cheerleading team plans to sell t-shirts as a fundraiser and the teams goal is to make profit of at least $1248 with each t-shirt sold at $6.50, then the equation required is;

6.50t ≥ 1246

Divide both sides by 6.50

6.50t/6.50 ≥1246/6.5

t ≥ 192

Hence the minimum number of shirt they will sell to make the given profit is 192 shirts

Learn more on inequality here: brainly.com/question/11613554

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8 0
1 year ago
Please explain i will mark brainliesttt!
Sati [7]

Answer:

<em>Answer is </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

given \: the \: line \: n \: passes \: through \\  \: ( - 3, - 7.5) \:  \: and(2, - 5) \\ the \: equation \: of \: the \: line \: is \\  \frac{y - y1}{y2 - y1}  =  \frac{x - x1}{x2 - x1}  \\ here \: x1 =  - 3 \:  \:  \: y1 =  - 7.5 \\ and \:  \: x2 = 2 \:  \:  \: y2 =  - 5 \\  \frac{y - ( - 7.5)}{ - 5 - ( - 7.5)}  =  \frac{x - ( - 3)}{2 - ( - 3)}  \\  \frac{y + 7.5}{ - 5 + 7.5}  =  \frac{x + 3}{2 + 3}  \\  \frac{y + 7.5}{2.5}  =  \frac{x + 3}{5}  \\ dividing \: by \: 5 \: on \: both \: side s\\  \frac{y + 7.5}{0.5}  =  \frac{x + 3}{1}  \\ 0.5(x + 3) = y + 7.5 \\ 0.5x + 1.5 = y + 7.5 \\ 0.5x - y - 6 = 0 \\ is \: the \: required \: equation.

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

5 0
3 years ago
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MA_775_DIABLO [31]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

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<u>Geometry</u>

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Step-by-step explanation:

<u>Step 1: Set up equation</u>

40° + (2x + 30)° + 40° = 180°

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Combine like terms:                    2x + 110 = 180
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