Answer: x<2, (negative infinity, 2)
Step-by-step explanation:
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
You must follow the steps below:
1. First, you should apply the dstributive property:
=(x²-<span>8x+15/3x)(8x/x-3)
=(8</span>x³-64x²+120x)/3x(x-3)
2. As you can see, the common factor in the numerator is: "8x". So, you have:
=8x(x²-8x+15)/3x(x-3)
3. Then, when you simplify, you obtain:
=8(x²-8x+15)/3(x-3)
Therefore, the solution is: 8(x²-8x+15)/3(x-3)
Solve the lower equation first
+12 on each side
7x=51
divide by 7
x=51/7
then use that to solve the upper equation
