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agasfer [191]
3 years ago
5

Suppose that initially the price is $50 in a perfectly competitive market. Firms are making zero economic profits. Then the mark

et demand shrinks permanently, some firms leave the industry, and the industry returns to a long-run equilibrium. What will be the new equilibrium price, assuming cost conditions in the industry remain constant?
a. $50.
b. $45.
c. Lower than $50 but exact value cannot be known without more information.
d. Larger than $45 but exact value cannot be known without more information.
Business
1 answer:
Serhud [2]3 years ago
6 0

Answer:

a. $50.

Explanation:

Since the cost conditions remain the same and the market in question is a perfectly competitive one, when the market returns to a long-run equilibrium, the equilibrium price gravitates towards the previous equilibrium price in which economic profit was zero, which is $50, regardless of some firms leaving the industry or not. Note that this behavior is only observed because this is a perfectly competitive market.

Therefore, the answer is alternative a. $50.

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Answer:

Cash Flow activities for each event are:

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b. Issued preferred stock              (Financing activity)

c. Paid cash dividends                   (Financing activity)

d. Net income                                  (Operating activity)

e. Sold equipment                         (Investing activity)

f.  Purchased treasury stock        (Financing activity)

g. Purchased patents                     (Investing activity)

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i. Sold long-term investments        (Investing activity)

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k. Issued common stock                (Financing activity)

<u>NOTE</u>

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7 0
3 years ago
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miskamm [114]
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5 0
3 years ago
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Lindsay​ Electronics, a small manufacturer of electronic research​ equipment, has approximately 6 comma 800 items in its invento
nignag [31]

Answer:

97.8 or 98 items

Explanation:

A items:

= Percent of items in inventory × No. of items

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B items:

= Percent of items in inventory × No. of items

= 0.31 × 6,800

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C Items:

= Percent of items in inventory × No. of items

= 0.59 × 6,800

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Units to be counted everyday:

=\frac{A\ items}{workings\ days} + \frac{B\ items}{workings\ days} + \frac{C\ items}{workings\ days}

=\frac{680}{22} + \frac{2,108}{61} + \frac{4,012}{124}

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7 0
3 years ago
Short paragraph about Junior Technical Assistant​
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Answer:

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Explanation:

8 0
3 years ago
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