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SIZIF [17.4K]
3 years ago
11

What is the net force on a 1,000 kg object accelerating at 3 m/s2 ?

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0
33 \leq m+1.4
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X = 5

AE and congruent to EC
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Plz help me plzzzzzzzzzz
Effectus [21]

Answer:

I think the answer is 7;

Step-by-step explanation:

All i did was subtract Q11 from all 4 of its sides;

11=4=7

7 0
3 years ago
What is 4r+9r-11r+7r please im not trying to fail
kaheart [24]

Answer:

9r

Step-by-step explanation:

combine like terms in PEMDAS order. Add 4, 9, and 7, then, subtract 11.

5 0
3 years ago
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16. J.D. opened a savings account with $425. After
snow_lady [41]

Answer:

1.2%

Step-by-step explanation:

Solving our equation

r = 10.2 / ( 425 × 2 ) = 0.012

r = 0.012

converting r decimal to a percentage

R = 0.012 * 100 = 1.2%/year

The interest rate required to

accumulate simple interest of $ 10.20

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over 2 years is 1.2% per year.

8 0
3 years ago
The frequency distributions of two data sets are shown in the dot plots below.
fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}

\text{Mean of data set 1}=\frac{45}{19}

\text{Mean of data set 1}=2.3684\approx 2.37  

\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}

\text{Mean of data set 2}=\frac{38}{18}

\text{Mean of data set 2}=2.11

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

\text{Median of data set 2}=\frac{2+2}{2}

\text{Median of data set 2}=\frac{4}{2}=2

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.


Q_1\text{ of data set 1}=1

Q_3\text{ of data set 1}=3

\text{IQR of data set 1}=3-1=2

Q_1\text{ of data set 2}=1

Q_3\text{ of data set 2}=3

\text{IQR of data set 2}=3-1=2

Since both data set's IQR is 2, therefore, 6th statement is true.

3 0
4 years ago
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