A rectangle has a perimeter of length + length + width + width.
L = length of the fence.
W = width of the fence.
so the perimeter will be L+L+W+W or 2L+2W or 2(L+W).
now, we know that 120 ⩽ 2(L+W).
we also know that 168 ⩾ 2(L+W)
and we also know that whatever the length is, is twice the width, or L = 2W.
There would be 1/8 of the pie left,
you have to add 3/4 and 1/8 to find the total eaten and then subtract it by 8/8 (the total) which would give you your answer.
Hope it helps
Answer:
h ≈ 7.816 cm
r ≈ 5.527 cm
Step-by-step explanation:
The volume of a cone is:
V = ⅓ π r² h
The lateral surface area of a cone is:
A = π r √(r² + h²)
1/4 of a liter is 250 cm³.
250 = ⅓ π r² h
h = 750 / (π r²)
Square both sides of the area equation:
A² = π² r² (r² + h²)
Substitute for h:
A² = π² r² (r² + (750 / (π r²))²)
A² = π² r² (r² + 750² / (π² r⁴))
A² = π² (r⁴ + 750² / (π² r²))
Take derivative of both sides with respect to r:
2A dA/dr = π² (4r³ − 2 × 750² / (π² r³))
Set dA/dr to 0 and solve for r.
0 = π² (4r³ − 2 × 750² / (π² r³))
0 = 4r³ − 2 × 750² / (π² r³)
4r³ = 2 × 750² / (π² r³)
r⁶ = 750² / (2π²)
r³ = 750 / (π√2)
r³ = 375√2 / π
r = ∛(375√2 / π)
r ≈ 5.527
Now solve for h.
h = 750 / (π r²)
h = 750 / (π (375√2 / π)^⅔)
h = 750 ∛(375√2 / π) / (π (375√2 / π))
h = 2 ∛(375√2 / π) / √2
h = √2 ∛(375√2 / π)
h ≈ 7.816
Notice that at the minimum area, h = r√2.
Answer:
( 3x − 1) ( 5x^2 + 2 )
Step-by-step explanation:
15x^3 − 5x^2 + 6x − 2
= ( 3x − 1) ( 5x^2 + 2 )
Answer:
0.308
Step-by-step explanation:
Given the data:
1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 6
The sample mean and standard deviation :
Sample mean, xbar = (1+1+2+2+2+3+3+3+3+4+4+6) / 12 = 2.833
Sample standard deviation, s = 1.40 ( calculator)
Hypothesis :
H0 : μ = 2.4
H0 : μ ≠ 2.4
The test statistic :
(xbar - μ) ÷ (s/√(n))
(2.833 - 2.40) / (1.40/sqrt(12))
Test statistic = 1.0713
Using the Pvalue from Test score calculator :
df = n - 1 = 12 - 1 = 11
Pvalue(1.071, 11) two - tailed
= 0.3069
= 0.307
