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storchak [24]
3 years ago
10

Diffusion and Solubility of Gases (B. Flaconn'eche, et al., Oil and Gas Science and Technology, 2001:262-278) reported on a stud

y of the effect of temperature and other factors on gas transport coefficients in semi crystalline polymers. The permeability coefficient (in 10-6 cm3 (STP)/cm. s. MPa) of CO2 was measured for extruded medium density polyethylene at both 60 degree C and 61 degree C. The results are as follows:
60⁰ C54516167576960606362
61⁰ C58606666686160

(1) Find Mean of 60 degree sample to nearest 0.1
(2) Find mean of 61 degree sample to nearest 0.1
(3) Find sample standard deviation of 60 degree sample to nearest 0.01
(4) Find Sample standard deviation of 61 degree sample to nearest 0.01
(5) What are the degrees of freedom?
(6) Center of Confidence interval? (7) Width of confidence interval (remember to multiply by 2?)
(8) If everything was the same except that we had one more sample in each group, would the above confidence interval get longer or shorter or stay the same?
Mathematics
1 answer:
yarga [219]3 years ago
5 0

Answer:

Step-by-step explanation:

see the attached file for the working and the answers, enjoy!

Download docx
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Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is <u>less than the standard significance level of 0.05</u>, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is <u>tested if the consumption is not different</u>, that is, if the subtraction of the means is 0, hence:

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The p-value of the test is found using a <u>two-tailed test</u>, as we are testing if the mean is different of a value, with <u>t = 2.2438</u> and 22 + 22 - 2 = <u>42 df.</u>

  • Using a t-distribution calculator, this p-value is of 0.0302.

Since the p-value of the test is of 0.0302, which is <u>less than the standard significance level of 0.05</u>, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

A similar problem is given at brainly.com/question/25600813

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