X =10.
First distribute the 2(2x-14) and get 4x-28.
x+2-4x-28. Subtract x from each side to get 2=3x-28.
Add 28 to both sides to equal 30=3x. Divide each side by 3 to get your final Answer, x=10.
Answer:
Step-by-step explanation:
A circle is inscribed in an equilateral triangle PQR with centre O. If angle OQR = 30°, what is the perimeter of the triangle?
This is a circle inscribed in an equilateral triangle with side s.
If you are asking for the perimeter of PQR, it is 3s.
If you are asking for the perimeter of OQR, it is (3+23–√3)s
Since OR and SR are the hypotenuses of right triangles with adjacent side equal to ½ s, their length is ½s / cos 30° = (√3) /3.
(3/3)s + ((√3) /3)s + ((√3) /3)s = ((3 + 2√3)/3)s ≈ 2.1547s
Hope it helps
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Answer:
0.38
Step-by-step explanation:
