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ArbitrLikvidat [17]
3 years ago
8

3.8*10 to the 9th power divided by 4*10 to the 2nd power

Mathematics
1 answer:
user100 [1]3 years ago
5 0

Answer:

9.5\times 10^{6}

Step-by-step explanation:

1. Divide the coefficients and the exponentials separately

\dfrac{3.8 \times 10^{9}}{4 \times 10^{2}} = \dfrac{3.8}{4} \times \dfrac{10^{9}}{10^{2}}

2. Divide the coefficients

\dfrac{3.8}{4} = 0.95

3. Divide the exponentials

Subtract the exponent in the denominator from the exponent in the numerator.

\dfrac{10^{9}}{10^{2}} = 10^{(9 - 2)} = 10 ^{7}

4. Re-join the new coefficient and the new exponential

\dfrac{3.8 \times 10^{9}}{4 \times 10^{2}} = 0.95 \times 10^{7}

5. Put the new number into standard form

The number before the power of 10 must be greater than or equal to one and less than 10.

Multiply the answer by 10/10.

(0.95 \times 10^{7}) \times \dfrac{10}{10} = (0.95\times10) \times \dfrac{10^{7}}{10} = \mathbf{9.5\times 10^{6}}

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Answer:

£5200

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 2%/100 = 0.02 per year,

then, solving our equation

I = 5000 × 0.02 × 2 = 200

I = £ 200.00

The simple interest accumulated

on a principal of £ 5,000.00

at a rate of 2% per year

for 2 years is £ 200.00.

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2 years ago
It takes a hose 2 minutes to fill a rectangular aquarium 12 inches long, 13 inches wide, and 14 inches tall. How long will it ta
rusak2 [61]

Volume of the first aquarium =  (12" x 13" x 14") = 2,184 inches³

Volume of the second aquarium = (32" x 34" x 35") = 38,080 inches³

The second aquarium has (38,080 / 2,184) = 17.44 times as much
volume as the first aquarium has.

So it'll take the hose  17.44 times as long to fill the second one

                              =  (17.44) x (2 minutes)  =  34.9 minutes.
8 0
3 years ago
Examples of properties communative, associative, and identity?
BlackZzzverrR [31]

Answer:

Communative: 12 x 5= 5 x 12 Associative: (5) + 6 = (8) + 3 Identity: 5 x 1= 5

Step-by-step explanation:

3 0
3 years ago
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If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumpe
lakkis [162]

If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper

Answer: We are given there are 49 cars

Also these 49 cars are in a line stretched 528 feet.

Now the average length of the car is:

Average length = \frac{(length-covered-by-49-cars)}{Number-of-cars}

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6 0
3 years ago
What is the area of ruth's mural?
pentagon [3]

Answer:

Step-by-step explanation:

Comment

The shape consists of a rectangle on the bottom and a trapezoid on the top.

Rectangle

A rectangle has a very simple Area formula. It is Area = L*W. In this case the L = 14 m and is horizontal. The width is at right angles to the length and is marked as 3.

Area = L * w

L = 14

w = 3

Area = 14 * 3 =                            42 m^2

Trapezoid

The trapezoid is a bit more complicated and some things have to be found. First of all b1 is the first base of the trapezoid. It is parallel to and equal to  the Length of the rectangle. b2 is marked 10 meters. The height is just a bit more complicated. The total height of the figure is 8 m. You can't count the 3 m of the rectangle as part of the height because b1 comes only to the top of the rectangle. The height is 8 - 3 = 5

Area = 1/2(b1 + b2)*h/2

b1 = 14

b2 = 10

h = 8 - 3 = 5

Area = 1/2 ( 14 + 10) * 5 / 2

Area = 1/2 (24)*5

Area = 12 * 5

Area =                                      <u>    60 m^2</u>

Total Area                                  102 m^2

8 0
2 years ago
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