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SVETLANKA909090 [29]
3 years ago
11

Which of the triangles in the diagram are congruent?

Mathematics
1 answer:
7nadin3 [17]3 years ago
7 0

Answer:

I would like to answer but where is the diagram. Download it to this page and i will answer your question. Have a great day

Step-by-step explanation:

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Whats6/24 in simplest form
MakcuM [25]
Count by 6 so 6×4 is 24 so 1/4
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3 years ago
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2y-____=0;y=0 HELPPPPPPP
AVprozaik [17]

Answer:

<em>D.)  0</em>

Step-by-step explanation:

Its not A.  cause 2y−2=0  is y = 1

Its not B. cause 2y−1=0  is y = 1/2

Its not C. cause 2y−3=0  is y = 3/2

Soo... The only option left is D.

It IS D. cause 2y − 0 = 0  is y=0

<em>So you are Correct!!!</em>

<em>hope I helped... <3</em>

<em>Good luck dear :)</em>

4 0
4 years ago
Why is tesla stock increasing/decreasing in value
Phantasy [73]

Answer:

elon musk

Step-by-step explanation:

elon sends out random, uncalled for tweets, which mess with the stock value.

For example, when the stock was very high, he tweeted,"Tesla stock too high"

7 0
3 years ago
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Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
3 years ago
Which angles are neither obtuse angles nor acute angles?
mr Goodwill [35]

Answer:

Acute angles are less than 90

obtuse is more than 90

right angles are exactly 90

Step-by-step explanation:

8 0
3 years ago
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