Answer:
a) d = 3.6t
b) 10.8 miles
c) 1.2 hours
Step-by-step explanation:
For part a:
Slope of a line: y = mx + b
In this case, the equation would be: d = mt,
where m represents the speed Caden is walking at.
Note: b = 0 in this case because when Caden starts walking on the treadmill, he hasn't really covered any distance yet.
Therefore, plugging in a speed of 3.6 miles per hour, the equation is:
d = 3.6t
For part b:
This is a simple instance of plugging in 3 hours for our t value.
Therefore, d = 3.6 (3)
d = 10.8 miles
For part c:
In this case, we are given that d = 4.32 miles.
Therefore, 4.32 = 3.6t
Dividing both sides by 3.6, we get
t = 1.2 hours
Answer:
Mean: 14
Median: 15
Mode: All values appear just once
Range: 7
Answer:
12
Step-by-step explanation:
You do what's in parentheses first, but everything is in parentheses so it's pretty much ineffective. In PEMDAS, addition and subtraction are coupled so you do them left to right. 6-1 is 5 and 5+7 is 12.
The sum of the magnitudes will be the magnitude of the sum when the vectors have the same direction.
The first thing I'll do is solve "5y = 2x + 20" for "<span>y=</span>", so that I can find my reference slope:
y = (2/5)x + 4;
So the reference slope from the reference line is <span>m = 2/5;</span>.
Now I need to find two new slopes, and use them with the point they've given me; namely, with the point (-1, 3). They want me to find the line through (4, –1) that is parallel to 5y = 2x + 20; that is, through the given point, they want me to find a line that has the same slope as the reference line.
Since a parallel line has an identical slope, then the parallel line through (-1, 3) will have slope <span>m = 2/5</span>. Now I have a point and a slope! So I'll use the point-slope form to find the line: y - 3 = (2/5)( x + 1);
Finally, y = (2/5)x + 17/5;
