Answer:
Answer: 3 1/2 and -10 1/2 are the two numbers.
Step-by-step explanation:
Let x and y be the two unknown numbers.
x+y=-7 [Given]
x-y=14 [Given]
x-y=14 [Given]
x=y+14 [Add y to both sides]
x+y=-7 [Given]
(y+14)+y=-7 [Subtitution]
2y+14=-7 [Combine like terms]
2y=-21 [Subtract 14 from both sides]
y=-21/2 [Divide both sides by 2]
y=-10 1/2 [Division]
x-y=14 [Given]
x=y+14 [Add y to both sides]
x=-10 1/2 + 14 [Substitution]
x= 3 1/2 [Addition]
Check:
x+y=-7 [Given]
3 1/2 + -10 1/2?=-7 [Substition]
-7=-7 [Addition]
QED
x-y=14 [Given]
3 1/2 - -10 1/2?=14 [Substitution]
3 1/2 + 10 1/2?=14 [Change the sign of the subtrahend and add]
14=14 [Addition]
QED
Answer: 3 1/2 and -10 1/2 are the two numbers.
Answer:
I am looking for this anwer to
Step-by-step explanation:
<span>for the first part, realize that the hour and minute hands are moving at different rates; in one hour, the minute hands moves all the way around the face of the clock, and thus moves a total of 360 degrees or 2 pi radians; the hour hand moves only 1/12 away around the clock, so covers only 30 degrees or Pi/6 radians.
Now, the LINEAR distance traveled by the tip of each hand is also determined by the length of the hand. In the case of the minute hand, it sweeps out a circle of radius 10 cm, so traces out a circle of radius 10 cm. Since the circumference of a circle is 2*pi*r, the minute hand (remember it made one complete cycle) covers a distance of 2*pi*10cm=20 Pi cm
The hour hand covers only 1/12 a circle, but that circle is only 6 cm in radius, so the distance traveled by the tip of the minute hand is:
1/12 *[2 *pi*r]=1/12*[12*pi]=pi
so the difference is 19pi
for the last part, you should draw a diagram of the two hands, the minute hand is 10 cm in length, the hour hand is 6 cm in length, and they are 30 degrees apart...from that drawing, see if you can figure out the remaining leg of the triangle you can form from them
good luck</span><span>
</span>
The constant would be 35 because a variable added onto it would make it a
