Mahalia is making cloth napkins. She bought fabric that is 12 inches wide and 6 yards long. How much napkins can Mahalia make if
1 answer:
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PART A
The given equation is
In order to find the maximum height, we write the function in the vertex form.
We factor -16 out of the first two terms to get,
We add and subtract
to get,
We again factor -16 out of the first two terms to get,
This implies that,
The quadratic trinomial above is a perfect square.
This finally simplifies to,
The vertex of this function is
The y-value of the vertex is the maximum value.
Therefore the maximum value is,
PART B
When the ball hits the ground,
This implies that,
We add -29 to both sides to get,
This implies that,
or
Since time cannot be negative, we discard the negative value and pick,
The given equation is
In order to find the maximum height, we write the function in the vertex form.
We factor -16 out of the first two terms to get,
We add and subtract
to get,
We again factor -16 out of the first two terms to get,
This implies that,
The quadratic trinomial above is a perfect square.
This finally simplifies to,
The vertex of this function is
The y-value of the vertex is the maximum value.
Therefore the maximum value is,
PART B
When the ball hits the ground,
This implies that,
We add -29 to both sides to get,
This implies that,
or
Since time cannot be negative, we discard the negative value and pick,
Step-by-step explanation:
In this case we have:
Δx = 3/n
b − a = 3
a = 1
b = 4
So the integral is:
∫₁⁴ √x dx
To evaluate the integral, we write the radical as an exponent.
∫₁⁴ x^½ dx
= ⅔ x^³/₂ + C |₁⁴
= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)
= ⅔ (8) + C − ⅔ − C
= 14/3
If ∫₁⁴ f(x) dx = e⁴ − e, then:
∫₁⁴ (2f(x) − 1) dx
= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx
= 2 (e⁴ − e) − (x + C) |₁⁴
= 2e⁴ − 2e − 3
∫ sec²(x/k) dx
k ∫ 1/k sec²(x/k) dx
k tan(x/k) + C
Evaluating between x=0 and x=π/2:
k tan(π/(2k)) + C − (k tan(0) + C)
k tan(π/(2k))
Setting this equal to k:
k tan(π/(2k)) = k
tan(π/(2k)) = 1
π/(2k) = π/4
1/(2k) = 1/4
2k = 4
k = 2
