Step-by-step explanation:
SinA=1/3=p/h
p=1,h=3,and b=?
Using Pythagoras Theorem,
b=√3^2-1^2
b=√9-1
b=√8=2√2
Now,
CosA=b/h=2√2/3
TanA=p/b=1/2√2
There is no phi in my keypad so I use A angle instead of phi.Adjust it.
Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C
A linear equation is a straight line. The equation is of the type y = MX + N
The soluction of that system is Ax^2 + Bx + C = MX + N
=> Ax^2 + (B-M)x + (C-N) = 0
That is a quadratic equation.
A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.
So you must select 0, 1 and 2.
You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.
You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.
The answer is 15*ln(m)-6*ln(n)
Answer:
a
Step-by-step explanation:
