Question

4. Diego is thinking of two positive numbers. He says, "If we triple the first number and

Answer 1

Answer:

3x + 2y = 34. and two possible pairs of positive numbers are  (x, y) = (10, 2) and (x, y) = (4, 11).

Step-by-step explanation:

 Let the First positive number be x and second positive number be y.

Triple of first number = 3x

double of second number = 2y

According to question,

3x + 2y = 34

Therefore, the equation is 3x + 2y = 34

So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3x + 2y = 34

Now,  3x + 2y = 34

3x = 34 - 2y

Let x = 10 and by substituting its value in above expression,

$3 \times 10 = 34 - 2y$

$30 = 34 - 2y$

$2y = 34 - 30$

$2y = 4$

$y = 2$

Therefore first pair (x, y) = (10, 2)

In the same way put x = 4 then,

3x = 34 - 2y

$3 \times 4 = 34 - 2y$

$2y = 34 - 12$

$2y = 22$

$y = 11$

Therefore first pair (x, y) = (4, 11)

Therefore, (x, y) = (4, 11) and  (x, y) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3x + 2y = 34.