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hram777 [196]
3 years ago
8

What is the solution of 1 / c - 3 - 1 / c = 3 / c(c - 3)?

Mathematics
2 answers:
netineya [11]3 years ago
7 0

\dfrac1{c-3}-\dfrac1c=\dfrac3{c(c-3)}

Combining the fractions on the left gives us

\dfrac c{c(c-3)}-\dfrac{c-3}{c(c-3)}=\dfrac{c-(c-3)}{c(c-3)}=\dfrac3{c(c-3)}

which is defined only as long as c\neq0 and c\neq3.

This expression is the same as the one on the right:

\dfrac3{c(c-3)}=\dfrac3{c(c-3)}

so and value of c, except c=0 and c=3 for the reason mentioned earlier, will be a solution, so the answer is C.

Murrr4er [49]3 years ago
7 0

Answer:

It's C. on EtDtGtE

Step-by-step explanation:

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Answer these please!
neonofarm [45]

Answer:

u shouldnt wasnt your points u know

Step-by-step explanation:

3 0
3 years ago
Is 237.5 less than or greater than 2 8/24
Schach [20]

Alright!

In order to properly compare these numbers, they need to look the same!

Lets change 2 8/24 into a <em>decimal.</em>

To do this, we need to convert it into an <u>improper fraction </u>

Follow these steps:

2 \frac{8}{24} \\

We multiply the<em> whole number</em> (2) by the <em>denominator </em>(24) and then add the <em>numerator </em>(8). The improper fraction will keep the same <em>denominator </em>(24) at the end.

2 × 24 = 48

48 + 8 = 56

\frac{56}{24}

Now, lets use a calculator to see what 56/24 is!

56 ÷ 24 = 2.33

237.5 is GREATER than 2 \frac{8}{24} \\

Hope I helped! Comment if you have questions :)

7 0
4 years ago
How do you do rate of change?
ahrayia [7]

Answer:

Y2-y1/x2-x1

Step-by-step explanation:

The rate of change is the same thing as slope. So you would do the same thing as you would for slope.

Ex. you have two coordinate points. (4,4) (5,9)

y2 would be 9

y1 would be 4

x2 would be 5

x1 would be 4

so you would do 9-4=5

then 5-4=1

So your rate of change/slope would be 5/1 or 5

7 0
3 years ago
Please help. and please explain the process too
denis-greek [22]
The polynomial as per the given of the problem is f(x)=3x²-21x+30
Find the roots of this polynomial:
 x₁=[-b+√b²-4ac)]/2a and x₂ =[-b-√b²-4ac)]/2a
Plug in : x₁ = [21+√(21²-4(3)(30)]/6 = [21+√81}/6 ; x₁ = 5
and x₂ = [21-√(21²-4(3)(30)]/6 = [21-√81]/6 ; x₂ = 2
 Remark: I don't understand where did you bring √5 , it should be 5
6 0
4 years ago
PLEASE HELP IM STUCK
Lapatulllka [165]

Step-by-step explanation:

2 equations with 2 variables.

the most common approach is

1. use one equation to express one variable by the other.

2. use this expression in the second equation and solve for the second variable.

3. use that solution in the original first equation and solve for the first variable.

the end.

0.05N + 0.10D = 2.20

N + D = 23

1. N = 23 - D

2. 0.05(23 - D) + 0.10D = 2.20

1.15 - 0.05D + 0.10D = 2.20

0.05D = 1.05

D = 1.05/0.05 = 21

3. N = 23 - D = 23 - 21 = 2

2 Nickels, 21 Dimes

5 0
1 year ago
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