The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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The first option, as it positively supports the claim stated.
Answer:
-8
Step-by-step explanation:
An equation at represents this situation is:
-5 = 3 + x
Find x by;
-5 - 3 = -8
So x is -8:
-5 = 3 + -8 (TRUE)
Hope this helps
Answer:
6
Step-by-step explanation:
The expression can be rearranged to ...
b = 3 -9/(a+5)
In order for b to be an integer, (a+5) must be an integer divisor of 9. There are exactly 6 of those: ±1, ±3, ±9.
The attached table shows the values (a, b) = (x₁, f(x₁)).
The best and most correct answer among the choices provided by your question is the second choice or letter B.
<span> CM is perpendicular to AB because the triangles are isosceles and scalene.
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