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3 years ago

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Mathematics

1 answer:

notsponge [240]3 years ago

3 0

Answer:

∠1=140

Step-by-step explanation:

∠1=∠3 ( corresponding angles)

20x+60=30x+20

-20x+30x=60-20

10x=40

x=4

∠1=20x+60=20(4)+60=140

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we do not know how much the price of a commodity is, but it has been reduced by 10% and now costs 20€. What was the starting pri

MrRissso [65]

I got 22 because if u do 20 multiplied by 10% that gives u 2 which u then add onto the 20 to get the starting price. 10% of 22 is 2 and then 22-2 = 20 (if u we’re doing it from the starting price)

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2 years ago

How do you write 31/50 as a percentage7k

Len [333]

31/50

31 ÷ 50 = 0.62

0.62 x 100 = 62%

So the answer is 62%

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4 0

3 years ago

Read 2 more answers

PLEASE HELP MEEEEEEEE

Angelina_Jolie [31]

Answer:

The moon equals 7

and the stars equal 4

Step-by-step explanation:

Equation 1:

(substitute the symbols for the numbers)

7 + 1 = 4 + 4 (<< This is correct, both sides equal 8)

Equation 2:

(again, substitute the symbols)

7 = 3 + 4

That is correct.

Hope this helped! Please give Brainiest!

(Asher)

3 0

3 years ago

work for a publishing company. The company wants to send two employees to a statistics conference. To be fair, the company deci

Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the conference is 0.10.

(d) The probability that John stays home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (M), Roberto (R), John (J), Dominique (D) and Clarice (C) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

${5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10$

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event E is:

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of Roberto and John is, RJ.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the conference as follows:

$P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10$

Thus, the probability that Roberto and John attend the conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the conference as follows:

$P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40$

Thus, the probability that Clarice attends the conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays home as follows:

$P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60$

Thus, the probability that John stays home is 0.60.

4 0

3 years ago

Please help me with this question :)

egoroff_w [7]

Answer:

Plot $3$ and $-3$

Step-by-step explanation:

Given:

$|2n| = 6$

Solving for the positive part of the equation:

$2n = 6 \\ \frac{2n}{2} = \frac{6}{2} \\ n = 3$

Solving for the negative part of the equation:

$-2n = 6 \\ \frac{-2n}{-2n} = \frac{6}{-2} \\ n = -3$

3 0

3 years ago