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tekilochka [14]
3 years ago
6

T object]user: the lengths of the sides of a certain triangle are 3, 4, and 5 respectively. what can you say about the triangle?

Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0
It is definitely a right triangle.
3^2 + 4^2 = 5^2

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Cual es el valor de 10=z-6
Sever21 [200]

Answer:

z=16

Step-by-step explanation:

10=z-6

10+6=z-6+6

16=z

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2 years ago
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Using the following diagram below, please answer the following:
Colt1911 [192]
The radius of the circle is 15 cm,
The diameter of the circle is 30 cm,
The circumference of the circle is 94.248 cm,
The area of the circle is 706.86 cm^2

The radius is given in the diagram as half the circle, which is 15 cm.

The diameter is double the radius because the diameter measures the circle from edge to edge, so 15•2=30 cm.

The circumference of the circle is 2•3.14•r=C,
2•3.14=6.28, 6.28•15= 94.248 cm.

The area of the circle is 3.14•r^2, so the radius squared is 225 (15•15) and 225•3.14=706.86 cm squared :)
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2 years ago
Which of the following statements is true?
wolverine [178]

Answer:

D: Point E is the midpoint of segment AC

Step-by-step explanation:

The midpoint is a point where it is in the middle of a line, line segment, or ray.

Congruent means something that is exactly the same.

Congruent triangles are two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure.

Bisect means separating something into two precise and equal pieces/ angles.

Similar triangles means two objects are similar if they have the same shape, or one has the same shape as the mirror image of the other.

8 0
3 years ago
Carly solved a quadratic equation by completing the square, but her work has errors. Identify the first error in Carly's work.
Savatey [412]

Answer:

Her first error was adding the wrong number to both sides. Instead of 4², it should be 2²

Step-by-step explanation:

When completing the square, the number that needs to be added to both sides is (b/2)²

In this problem, b is 4. So, Carly should have added 2² to both sides, but she added 4² instead.

So, her first error was adding 4² to both sides instead of 2²

8 0
3 years ago
Suppose the test scores for a college entrance exam are normally distributed with a mean of 450 and a s. d. of 100. a. What is t
svet-max [94.6K]

Answer:

a) 68.26% probability that a student scores between 350 and 550

b) A score of 638(or higher).

c) The 60th percentile of test scores is 475.3.

d) The middle 30% of the test scores is between 411.5 and 488.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 450, \sigma = 100

a. What is the probability that a student scores between 350 and 550?

This is the pvalue of Z when X = 550 subtracted by the pvalue of Z when X = 350. So

X = 550

Z = \frac{X - \mu}{\sigma}

Z = \frac{550 - 450}{100}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 350

Z = \frac{X - \mu}{\sigma}

Z = \frac{350 - 450}{100}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a student scores between 350 and 550

b. If the upper 3% scholarship, what score must a student receive to get a scholarship?

100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So it is X when Z = 1.88

Z = \frac{X - \mu}{\sigma}

1.88 = \frac{X - 450}{100}

X - 450 = 1.88*100

X = 638

A score of 638(or higher).

c. Find the 60th percentile of the test scores.

X when Z has a pvalue of 0.60. So it is X when Z = 0.253

Z = \frac{X - \mu}{\sigma}

0.253 = \frac{X - 450}{100}

X - 450 = 0.253*100

X = 475.3

The 60th percentile of test scores is 475.3.

d. Find the middle 30% of the test scores.

50 - (30/2) = 35th percentile

50 + (30/2) = 65th percentile.

35th percentile:

X when Z has a pvalue of 0.35. So X when Z = -0.385.

Z = \frac{X - \mu}{\sigma}

-0.385 = \frac{X - 450}{100}

X - 450 = -0.385*100

X = 411.5

65th percentile:

X when Z has a pvalue of 0.35. So X when Z = 0.385.

Z = \frac{X - \mu}{\sigma}

0.385 = \frac{X - 450}{100}

X - 450 = 0.385*100

X = 488.5

The middle 30% of the test scores is between 411.5 and 488.5.

7 0
3 years ago
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