I believe the slope is -1
Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:
190% of 66= 125.4
rounded to the nearest tenth:130
Answer:
P(O and O) =0.1296
P=0.3778
Step-by-step explanation:
Given that
blood phenotypes in a particular population
A=0.48
B=0.13
AB=0.03
O=0.36
As we know that when A and B both are independent that
P(A and B)= P(A) X P(B)
The probability that both phenotypes O are in independent:
P(O and O)= P(O) X P(O)
P(O and O)= 0.36 X 0.36 =0.1296
P(O and O) =0.1296
The probability that the phenotypes of two randomly selected individuals match:
Here four case are possible
So
P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)
P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36
P=0.3778
Answer: the answer is 809
Step-by-step explanation:
