36 and 48
a = b+12
a+b = 84
(b+12) + b =84
2b +12 = 84
2b = 72
b= 36
a = b + 12
a = 36 + 12
a = 48
Answer:
CE = 17
Step-by-step explanation:
∵ m∠D = 90
∵ DK ⊥ CE
∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK
In the two Δ KDE and KCD:
∵ m∠KDE = m∠KCD
∵ m∠DKE = m∠CKD
∵ DK is a common side
∴ Δ KDE is similar to ΔKCD
∴ 
∵ DE : CD = 5 : 3
∴ 
∴ KD = 5/3 KC
∵ KE = KC + 8
∵ 
∴ 
∴ 
∴ 
∴ 
∴ KC = (8 × 9) ÷ 16 = 4.5
∴ KE = 8 + 4.5 = 12.5
∴ CE = 12.5 + 4.5 = 17
Answer:
A dress originally costs $120
Step-by-step explanation:
To find the original cost of the dress, we will follow the steps below;
let x represent the original cost of the dress
75% of x = $90
× x = $90
= $90
MULTIPLY both-side of the equation by 100
× 100 = $90×100
At the right-hand side of the equation, 100 will cancel out 100, leaving us with just 75x
75x = $9000
DIVIDE both-side of the equation by 75
75x/75 = $9000/75
At the left-hand side of the equation 75 will cancel-out 75 leaving us with just x
x= $9000/75
x = $120
A dress originally costs $120
Answer:
A
Step-by-step explanation:
Using the sine ratio in the right triangle
sin40° =
=
= 
Multiply both sides by 7, thus
AC = 7sin40° → A
1.) -8 + 10(6 + 4r)
First multiply the 10 into (6 + 4r)
-8 + 60 + 40r
52 + 40r
2.) (8m² - 8m + 8) - (2m - 7m² - 6)
Distribute the - into (2m - 7m² - 6)
8m² - 8m + 8 - 2m + 7m² + 6
Combine like terms
15m² - 10m + 14
(idk if you need to factor this or if you can leave it as is)