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lisabon 2012 [21]
3 years ago
7

Dotti and Bud bought two identical watermelons. Dotti cut her watermelon into 3 pieces and ate 2 of the pieces. Dud cut his wate

rmelon into 9 pieces, but ate the exact same amount of watermelon as Dotti. How many of 9 pieces must he have eaten of hes watermelon? Explain your answer.
Mathematics
2 answers:
kondaur [170]3 years ago
5 0

Answer:

Bus must have eaten 6 pieces of his watermelon.

Step-by-step explanation:

We have been given that  Dotti and Bud bought two identical watermelons. Dotti cut her watermelon into 3 pieces and ate 2 of the pieces. This means Dotti has eaten 2/3 of his watermelon.

Bud cut his watermelon into 9 pieces, but ate the exact same amount of watermelon as Dotti.

We will use proportions to solve our given problem as proportions states that two fractions are equivalent.

\frac{\text{Pieces of watermelon eaten by Bud}}{\text{Total pieces of Bud's watermelon}}=\frac{\text{Pieces of watermelon eaten by Dotti}}{\text{Total pieces of Dotti's watermelon}}

Upon substituting our given values in above proportion we will get,

\frac{\text{Pieces of watermelon eaten by Bud}}{9}=\frac{2}{3}

Let us multiply both sides of our equation by 9.

\frac{\text{Pieces of watermelon eaten by Bud}}{9}*9=\frac{2}{3}*9

\text{Pieces of watermelon eaten by Bud}=2*3

\text{Pieces of watermelon eaten by Bud}=6

Therefore, Bud must have eaten 6 pieces of his watermelon.

Let us cross check our answer by substituting 6 in our proportion as:

\frac{6}{9}=\frac{2}{3}

\frac{2}{3}=\frac{2}{3}

Hence, proved.


denpristay [2]3 years ago
4 0

Answer:

Bud have eaten 2 pieces as Bud and Dotti have eaten exact same amount.

Step-by-step explanation:

We have been given Dotti and Bud bought two identical watermelons

Dotti cut her watermelon into 3 pieces and ate 2 of the pieces.

Bud cut watermelon into 9 pieces

But Dotti  and Bud have eaten exact same amount of watermelon

That means if Dotti have eaten 2 pieces then Bud would also have eaten 2 pieces out of 9.

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<em>See Attachment for complete question</em>

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