Question

Writing a recursive formula..

Answer 1

$a_1=\frac{24}{2^1}+4=16\\\\a_2=\frac{24}{2^2}+4=10\\\\a_3=\frac{24}{2^3}+4=7\\\\a_4=\frac{24}{2^4}+4=5.5\\\\a_5=\frac{24}{2^5}+4=4.75\\\\a_6=\frac{24}{2^6}+4=4.375\\\vdots\\a_n=\frac{24}{2^n}+4$

Answer 2

A1=21+24/2!=16

Hope I helped