Plz help me !!!!!!!.........

Mathematics

2 answers:

Andreas93 [3]2 years ago

8 0

I believe the correct answer is a hope this helps

Blababa [14]2 years ago

3 0

The answer is a because each input (x) has to have one output (y) to be a function

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Classify each polynomial according to its degree and type. Look at the screenshot below!

Ahat [919]

Answer:

Monomial Binominal Trimoninal

Degree 1: -9x x + 6

Degree 2: -4 $x^{2}$ $4x^{2} -x$ $x -3x^{2} + 1$

Degree 3: 4 $x^{3}$ 5 - 2 $x^{3}$ $3x^{2} + 3x^{3} -10$

Step-by-step explanation:

I do not know how to explain how I got to this answer, but here is the answer.

8 0

2 years ago

Rectangle ABCD is reflected over the y-axis. What rule shows the input and output of the reflection, and what is the new coordin

Vitek1552 [10]

Solution:

As given Rectangle ABCD is reflected over the y- axis.

When a shape or geometrical figure is reflected through a line it's distance that is distance of image from line and distance of Pre-image from that line is always same.Also perpendicular distance of vertices of any polygon that is considered for reflection has same distance from that line after reflection and before reflection.

Suppose the coordinate of A be (x,y) and considering Rectangle A B CD lie in first quadrant then when it is reflected through y - axis that is through the line x=0, it's new coordinate will become A' (-x,y).

If rectangle is in second quadrant having Vertices that is vertices of A (-x,y) then reflected over line that is x=0,→ y axis then Vertices of A' (x,y).

If rectangle is in third quadrant having Vertices that is vertices of A (-x,-y) then reflected over line that is x=0,→ y axis then Vertices of A' (x,-y).

If rectangle is in fourth quadrant having Vertices that is vertices of A (x,-y) then reflected over line that is x=0,→y axis then Vertices of A' (-x,-y).

6 0

3 years ago

At an airport, it cost 7 to park for one hour and 5 per hour for each additional hour.Let x represent the number hours parked.wr

kompoz [17]

The cost of parking is an initial cost plus an hourly cost.
The first hour costs $7.
You need a function for the cost of more than 1 hour,
meaning 2, 3, 4, etc. hours.
Each hour after the first hour costs $5.

1 hour: $7
2 hours: $7 + $5                  = 7 + 5 * 1          = 12
3 hours: $7 + $5 + $5          = 7 + 5 * 2          = 17
4 hours: $7 + $5 + $5 + $5 = 7 + 5 * 3          = 22

Notice the pattern above in the middle column.
The number of $5 charges you add is one less than the number of hours.
For 2 hours, you only add one $5 charge.
For 3 hours, you add two $5 charges.

Since the number of hours is x, according to the problem, 1 hour less than the number of hours is x - 1.

The fixed charge is the $7 for the first hour.
Each additional hour is $5, so you multiply 1 less than the number of hours,
x - 1, by 5 and add to 7.

C(x) = 7 + 5(x - 1)

This can be left as it is, or it can be simplified as

C(x) = 7 + 5x - 5

C(x) = 5x + 2

Answer: C(x) = 5x + 2

Check:
For 2 hours: C(2) = 5(2) + 2 = 10 + 2 = 12
For 3 hours: C(3) = 5(3) + 2 = 15 + 2 = 17
For 4 hours: C(3) = 5(4) + 2 = 20 + 2 = 22
Notice that the totals for 2, 3, 4 hours here
are the same as the right column in the table above.

6 0

3 years ago

A point P is moving along the curve whose equation is y = \sqrt x . Suppose that x is increasing at the rate of 4 units/s when x

Mice21 [21]

Answer:3 units/s

Step-by-step explanation:

Given

$y=\sqrt{x}$