What is the equation, in slope-intercept form, of the line that passes through (0,6) and has a slope of 4?

2 answers:

5 0

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{6})~\hspace{10em} slope = m\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-6=4(x-0) \\\\\\ y-6=4x\implies y=4x+6$

Nikitich [7]3 years ago

3 0

C. Y=6x-4 would be the answer

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First you need to isolate the variable so for #1 I would add 2t on both sides and add 3 on both sides. That makes the inequality -4t<-16. Then divide both sides by -4 to get t<4. This means that t is less than 4 so you need to draw an open circle on four on the number line and draw an arrow pointing to everything less than 4. ( If the inequality is equal to and less than/ greater than a # shade in the circle.)

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