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elena-s [515]
2 years ago
10

A prism has a volume of 225 cubic meters.

Mathematics
1 answer:
SOVA2 [1]2 years ago
7 0

Answer: Its D

Step-by-step explanation:

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Help with this question pls
GrogVix [38]

Answer:

B .75

Step-by-step explanation:

hope this helped <3

4 0
2 years ago
Find the midpoint of the segment with the given endpoints.
Ksju [112]

The mid-point for given endpoints is (4,3)

Step-by-step explanation:

a mid-point is the point on a line segment that divides it into two equal portions.

If (x1,y1) and (x2,y2) are the coordinates of vertices of a line segment, then mid-point is given by:

M = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

given

(x1,y1) = (9,9)

(x2,y2) = (-1,-3)

M = (\frac{9-1}{2}, \frac{9-3}{2})\\\\=(\frac{8}{2}, \frac{6}{2})\\\\=(4,3)

The mid-point for given endpoints is (4,3)

Keywords: Coordinate Geometry, Mid-point

Learn more about coordinate geometry at:

  • brainly.com/question/4639731
  • brainly.com/question/4655616

#LearnwithBrainly

5 0
3 years ago
Multiply.<br> 3/4 x -5 1/6
navik [9.2K]

Answer:

-3.87500

Step-by-step explanation:

brainliest!! plez

5 0
3 years ago
1. Find the ratio of of 25cm and 1m .<br> 2. Find the product of (a + 4)(a − 4).
mr Goodwill [35]

Answer:

1..

solution....

here given

25cm

1m=100cm

now,

25/100=1/4

1:4

2....

(a+4)(a-4)

a^2-4^2

a^2-16

Step-by-step explanation:

hope it will help you

7 0
3 years ago
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
3 years ago
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