5^3=125; 2.5^2=6.25. So the answer to your first question is 125, and the second one is 6.25
Answer:
1/ 3
Step-by-step explanation:
If each of the cards is turned over, the probability of picking up a card of one type P(E) becomes equal to:
=> P(E) = number of cards of the required type/ total number of cards
● Total number of spades( ♤ ) = 3
{the queen, one ace and the nine are all spades}
● Total number of cards = 6
Probability of drawing a spade= 3/ 6
= 1/ 2
● Total number of "7" = 1
● Total number of cards = 6
Probability of drawing a 7
= 1/ 6
Now, what's asked is the difference in the probabilities of drawing a spade and a seven.
= 1/ 2 - 1/ 6
= 3/ 6 - 1/ 6
= 2/ 6
= 1/ 3
Hence, 1/ 3 of a greater chance of drawing a spade over a 7.
Answer:
-5n
Step-by-step explanation:
n-6n=-5n
Hope This Helps!!
(brainliest please, if possible)
