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Paha777 [63]
3 years ago
10

Help please like hurry!!

Mathematics
2 answers:
makvit [3.9K]3 years ago
8 0

Answer: 36 square inches

Step-by-step explanation: The trapezoid is divided into three triangles.

The formula for the area of a triangle is 1/2(b*h). Replace the variables with the values in the drawing.

1/2(4*6)

= 1/2(24)

=12

There are 3 triangles, so multiply the area of 1 triangle (which is 12) by 3.

12*3

=36

Label the final answer.

36 square inches

adelina 88 [10]3 years ago
5 0
The answer is a 36
This is because if you take the area of one of the three triangles that make up the trapezoid you do 1/2 base times height and get 12 and you add all three together thus getting 36 square inches
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IrinaK [193]

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27

Step-by-step explanation:

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3 years ago
P(-3,6), Q(-3,-6) and R(6,-2) are the vertices of a triangle. Calculate the perimeter of this triangle.​
Eva8 [605]

Answer:

33.89

Step-by-step explanation:

the side lengths are the distances between the corner points of the triangle.

P and Q have the same x value, and they therefore create a side parallel to the y-axis. and it is easy to find the length of this side : it is just the difference of the y values.

PQ = 6 - (-6) = 6 + 6 = 12

QR and RP are trickier.

we need Pythagoras to calculate the length of the direct connection between these points as the Hypotenuse of the right triangles with the differences in x and in y values as the other sides.

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QR² = (-3 - 6)² + (-6 - -2)² = (-9)² + (-4)² = 81 + 16 = 97

QR = sqrt(97) ≈ 9.848857802

RP :

RP² = (6 - -3)² + (-2 - 6)² = 9² + (-8)² = 81 + 64 = 145

RP = sqrt(145) ≈ 12.04159458

the perimeter/circumference of the triangle is the sum of all 3 sides

= 12 + sqrt(97) + sqrt(145) ≈ 33.89

3 0
3 years ago
Can someone PLEASE help me with Trigonometry???
Svetach [21]
\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}

but anyway, the numerator will give the angles, and θ is just half of each

\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there
7 0
3 years ago
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Answer:

I would say 6 or 4, if we don't know which direction <u>he</u><u> </u><u>is</u><u> </u><u>walking</u><u> </u>

7 0
3 years ago
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