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Alinara [238K]
3 years ago
8

What's the dot product of u = <-9, 4> and v = <1,3>? Thanks!

Mathematics
1 answer:
Leno4ka [110]3 years ago
8 0
\langle-9,4\rangle\cdot\langle1,3\rangle=(-9)(1)+(4)(3)=-9-12=-21
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3eighths - negitive 5 and 1 fourths
WITCHER [35]
Sorry, what exactly is the question?
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A CD with a diameter of 120 millimeters rotates a rate of 45 revolutions per minute. Find the linear speed of the CD in millimet
ale4655 [162]

9514 1404 393

Answer:

  • 16,965 mm/min
  • 90π ≈ 282.7 radians/min

Step-by-step explanation:

The circumference of the CD is ...

  C = πd

  C = π(120 mm) ≈ 376.99 mm

This is the distance a point on the edge of the CD will travel when making one revolution. It will travel 45 times this far when making 45 revolutions:

  (376.99 mm/rev)(45 rev/min) ≈ 16,965 mm/min

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There are 2π radians in each revolution, so the angular speed is ...

  (2π rad/rev)(45 rev/min) = 90π rad/min ≈ 282.7 rad/min

6 0
3 years ago
A cube shaped container has an edge length of 2/3 feet what is the volume of the container
Dahasolnce [82]
To find the volume, you cube the edges.
So make it easier, you can cube the numerator and then the denominator.
2*2=4*2=8
3*3=9*3=27
8/27
You cannot simplify it any more.
The volume of the container is 8/27 feet cubes.
3 0
3 years ago
Solve for x. 5x - 1 = 26 x = x = 5 x = -5
Doss [256]

Answer:

x = 27/5

Step-by-step explanation:

5x - 1 = 26

Add 1 to each side

5x - 1 = 26

5x-1+1 = 26+1

5x = 27

Divide each side by 5

5x/5 = 27/5

x = 27/5

5 0
3 years ago
There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th
N76 [4]

Answer:

a. 40320 ways

b. 10080 ways

c. 25200 ways

d. 10080 ways

e. 10080 ways

Step-by-step explanation:

There are 8 different jobs in a printer queue.

a. They can be arranged in the queue in 8! ways.

No. of ways to arrange the 8 jobs = 8!

                                                        = 8*7*6*5*4*3*2*1

No. of ways to arrange the 8 jobs = 40320 ways

b. USU comes immediately before CDP. This means that these two jobs must be one after the other. They can be arranged in 2! ways. Consider both of them as one unit. The remaining 6 together with both these jobs can be arranged in 7! ways. So,

No. of ways to arrange the 8 jobs if USU comes immediately before CDP

= 2! * 7!

= 2*1 * 7*6*5*4*3*2*1

= 10080 ways

c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

Then, with a gap of five spaces, USU will come at the first place and CDP at the seventh. We will have two such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 2 * 6!

Finally, with a gap of 6 spaces, USU at first place and CDP at the last, we can arrange the rest of the jobs in 6! ways.

So, total no. of different ways to arrange the jobs such that USU comes before CDP = 10080 + 6*6! + 5*6! + 4*6! + 3*6! + 2*6! + 1*6!

                    = 10080 + 4320 + 3600 + 2880 + 2160 + 1440 + 720

                    = 25200 ways

d. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways. Similarly, if LPW comes last, the remaining 7 jobs can be arranged in 7! ways. so, total no. of different ways in which the eight jobs can be arranged is 7! + 7! = 10080 ways

e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

3 0
3 years ago
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