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mote1985 [20]
3 years ago
5

Me ayudan son ecuaciones ✨

Mathematics
1 answer:
Serggg [28]3 years ago
8 0

Answer:

Yo no entiendo que tu quieres desir

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Here is the imagine of the triangle ABC and it’s dilations using center D and scale factor 2
Nastasia [14]

(3) The question state that we should explain the relationship between angle ACB and A'C'B' in the given diagram.

From the the diagram in the question, we can see that wa have two different triangle which are ABC and A'B'C'.

The relationship between angle ACB and angle A'C'B' is that they are corresponding angles. because they are on the same side of the line.

Corresponding angles are any pair of angles each of which is on the same side of one of two lines cut by a trasnsversal and on the same side of the transversal.

Therefore, the relationship between angle ACB and angle A'C'B' is that they are corresponding angles.

6 0
1 year ago
......//...//../././//..//.././.?
igomit [66]

Answer:.//./././/..

Step-by-step explanation:.././././..././..././//...../

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3 years ago
Which number is an integer?<br><br> A) -9,248.3<br> B) 35,749.087<br> C)10,839<br> D -16/17
Cerrena [4.2K]

Answer:

C) 10839

Step-by-step explanation:

.For example, 21, 4, 0, and −2048 are integers, while 9.75, 512, and √2 are not.

3 0
3 years ago
Use the Pythagorean theorem to find the unknown side of the right triangle.
Nesterboy [21]

The length of hypotenuse is 39.

Step-by-step explanation:

Given,

Vertical side = a = 15

Horizontal side = b = 36

Hypotenuse = c

Using pythagorean theorem

a^2+b^2=c^2\\(15)^2+(36)^2=c^2\\225+1296=c^2\\1521=c^2\\c^2=1521

Taking square root on both sides

\sqrt{c^2}=\sqrt{1521}\\c=39

The length of hypotenuse is 39.

Keywords: square root, addition

Learn more about square roots at:

  • brainly.com/question/9196410
  • brainly.com/question/9178881

#LearnwithBrainly

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4 years ago
Peter paid $12.83 for a dvd. The price of the dvd was $11.98. How much sales tax did peter pay?
ArbitrLikvidat [17]
Peter paid 0.85 tax which is at 7.1% sales tax
6 0
3 years ago
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