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Oksanka [162]
3 years ago
5

If you have three friends, how many ways can you introduce them to someone?

Mathematics
2 answers:
Phantasy [73]3 years ago
6 0
6 ways to introduce them
Sedbober [7]3 years ago
6 0

Answer: 6

Step-by-step explanation:

Given : The number of friends : 3

If we introduce one by one , then the number of ways to introduce them is given by permutations .

We can choose first friend in 3 ways , second in 2 and the third in one way.

Then , the number of ways of introducing 3 friends one at a time is given by :-

3!=3\times2\times1=6

Therefore, the  number of ways of introducing 3 friends  = 6

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Jordi trains on his bicycle by riding for a total of 300 miles each week.
Alex73 [517]
Since y represents miles and x represents weeks, it would be y=300x
7 0
2 years ago
Cos 0 = 12/13. Find sin 0.<br> A. 5/12<br> B. 12/5<br> C. 13/12<br> D. 5/13
andreyandreev [35.5K]

Answer:

Sine θ = 5/13

Step-by-step explanation:

From the question given above, the following data were obtained:

Cos θ = 12/13

Sine θ =?

Next, we shall determine the opposite. This can be obtained as follow:

Cos θ = Adjacent /Hypothenus

Cos θ = 12/13

Adjacent = 12

Hypothenus = 13

Opposite =?

Hypothenus² = Opposite² + Adjacent²

13² = Opposite² + 12²

169 = Opposite² + 144

Collect like terms

169 – 144 = Opposite²

25 = Opposite²

Take the square root of both side

Opposite = √25

Opposite = 5

Finally, we shall determine the Sine θ. This can be obtained as follow:

Opposite = 5

Hypothenus = 13

Sine θ =.?

Sine θ = Opposite / Hypothenus

Sine θ = 5/13

8 0
2 years ago
Ivan flips a coin 40 times, How many times can he expect head to appear?
aleksklad [387]
The answer is a lol haha
6 0
2 years ago
Read 2 more answers
WILL MARK BRAINLIEST IF CORRECT❤️❤️<br> Simplify the expression -5+i/2i<br> Step by step
zhenek [66]

Answer:

For complex numbers,

a + bi and a - bi

they have the interesting property that if you add them you get the real number 2a

and if you multiply them , because of the difference of square pattern, you get a^2 - b^2 i^2

But since i^2 = -1, we end up with a real number as a product.

e.g. 6 - 5i and 6 + 5i are conjugates of each other

sum = 6-5i + 6+5i = 12

product = 36 - 25i^2

= 36 -(-25) = 61

Your question is even easier, since the denominator is a monomial instead of a binomial, so we just have to multiply by i/i

Also I believe, according to the answer, that you have a typo, and you meant

(-5+i)/(2i)

= (-5+i)/(2i) *i/i

= (-5i + i^2)/2i^2)

= (-5i +i^2)/-2

= (-5i - 1)/-2

= (1 + 5i)/2 or they way they have it: 1/2 + 5i/2

5 0
2 years ago
Read 2 more answers
Please help,
Bess [88]

It is A bc (4)=7(1)-3

5 0
3 years ago
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