Since there are only 4 terms in the sum, it's not too much work to expand it as
Alternatively, we can use the well-known formulas
These sums start at n = 0, so in our given sum we will keep track of the 0-th term separately:
as expected.
Y = ( 3 / 4 )x - 4 and ( 3 / 2 )x + ( 3 / 4 )y = 16 ;
Then, ( 3 / 2 )x + ( 3 / 4 )[ ( 3 / 4 )x - 4 ] = 16 ;
( 3 / 2 )x + ( 9 / 16 )x - 3 = 16 ;
( 3 / 2 )x + ( 9 / 16 )x = 19 ;
( 24 / 16 )x + ( 9 / 16 )x = 304 / 16 ;
24x + 9x = 304 ;
33x = 304 ;
x = 9.(21);
y = ( 3 / 4 ) × 9.(21) - 4 = 2.90 ;
The zeros of a quadratic equation are equal to the x-intercepts of its graph. In other words, you must find the x-value that causes the expression to equal zero. Start by adding 4 to both sides of the equation:
X² - 5x + 4 = 0
Factor the equation:
(x - 1)(x - 4) = 0
Now calculate each piece separately, starting with the first one:
x - 1 = 0
Add 1 to both sides of the equation:
x = 1
We have proven that x = 1. Now calculate the second piece:
x - 4 = 0
Add 4 to both sides of the equation:
x = 4
We have proven that x = 4. Consequently, we have proven that (x = 1) and (x = 4) are the two zeros of this quadratic equation.
I hope this helps!
Answer:
yes
Step-by-step explanation:
no
