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geniusboy [140]
2 years ago
5

Find the value of x in the triangle shown below

Mathematics
2 answers:
8_murik_8 [283]2 years ago
6 0

Answer:

A) x=3

Step-by-step explanation:

5^2-4^2=9

x=sq rt 9=3

pshichka [43]2 years ago
4 0
Answer:

x = 3

Explanation:

The one way you can figure this out is by using Pythagorean Theorem (a^2 + b^2 = c^2). If you did that, you’d get:

4^2 + b^2 = 5^2

If you solved this problem, you’d get b = 3.
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Answers to fill in this table?????
Sladkaya [172]

The total of can counts - 397

The total  of cannot counts - 110

Total number of boys - 263

Total number of girls - 244

The FULL total - 507

3 0
3 years ago
Suppose that scores on an aptitude test are normally distributed with a mean of 100 and a standard deviation of 4.6. Scores on a
DerKrebs [107]

Answer:

<u>The correct answer is C. Felix's z-score on the aptitude test was 1.30. His z-score on the knowledge test was 2.08. Felix performed better on the knowledge test, comparatively.</u>

Step-by-step explanation:

1. Let's check all the information given to us to answer the question correctly:

Mean of the scores on the aptitude test = 100

Standard deviation of the aptitude test = 4.6

Felix's score on the aptitude test = 106

Mean of the scores on the knowledge test = 70

Standard deviation of the knowledge test = 2.4

Felix's score on the knowledge test = 75

2. Which statement best describes Felix's scores on the two tests comparatively?

Let's recall that z-score in a normal distribution, positive or negative, is the number of times of the standard deviation a certain element is from the mean. If the element is below the mean, then the z-score is negative and if it's above the mean, then the z-score is positive.

Therefore, a score of 106 on the aptitude test, will have the following z-score:

106 - 100 = 6 and it's above the mean.

Now, we calculate the z-score, using the value of the standard deviation this way:

6/4.6 = 1.30

A score of 75 on the knowledge test, will have the following z-score:

75 - 70 = 5 and it's above the mean.

Now, we calculate the z-score, using the value of the standard deviation this way:

5/2.4 = 2.08

The z-scores of Felix were 1.30 on the aptitude test and 2.08 on the knowledge test. He performed better on the aptitude test because 2.08 > 1.30, so the correct statement that best describes Felix's scores on the two tests comparatively is<u> C. Felix's z-score on the aptitude test was 1.30. His z-score on the knowledge test was 2.08. Felix performed better on the knowledge test, comparatively.</u>

6 0
3 years ago
Write an equation using “” and then solve the equation. The late fee for each day is $2. A patron paid $72 for books that are ov
topjm [15]
Pretty simple equation, where we need to find the number of books. If it is 2$ each day per book
72/9 = 8$ per day is the late fee paid
So if each book is 2$, then we can assume
8/2 = 4 books

So equation is
“# books = (amount paid)/(days * per day payment)”
4 0
2 years ago
A type ii error occurs when: the sample mean differs from the population mean the null hypothesis is incorrectly accepted when i
svetlana [45]
A) the null hypothesis is incorrectly accepted when it is false
3 0
3 years ago
For 0 ≤ θ &lt; 2 π what are the solutions to sin^2(θ) =2sin^2(θ/2)
gregori [183]

Recall the half-angle identity for sine,

sin²(x/2) = (1 - cos(x))/2

Then the given equation is identical to

sin²(θ) = 1 - cos(θ)

Also recall the Pythagorean identity,

sin²(θ) + cos²(θ) = 1

Then we rewrite the equation as

1 - cos²(θ) = 1 - cos(θ)

Factoring the left side, we have

(1 - cos(θ)) (1 + cos(θ)) = 1 - cos(θ)

and so

(1 - cos(θ)) (1 + cos(θ)) - (1 - cos(θ)) = 0

and we factor this further as

(1 - cos(θ)) (1 + cos(θ) - 1) = 0

which gives

cos(θ) (1 - cos(θ)) = 0

Then either

cos(θ) = 0   or   1 - cos(θ) = 0

cos(θ) = 0   or   cos(θ) = 1

[θ = arccos(0) + 2nπ   or   θ = -arccos(0) + 2nπ]

…   or   [θ = arccos(1) + 2nπ   or   θ = -arccos(1) + 2nπ]

(where n is any integer)

[θ = π/2 + 2nπ   or   θ = -π/2 + 2nπ]   or   [θ = 0 + 2nπ]

In the interval 0 ≤ θ < 2π, we get three solutions:

• first solution set with n = 0   ⇒   θ = π/2

• second solution set with n = 1   ⇒   θ = 3π/2

• third solution set with n = 0   ⇒   θ = 0

So, the first choice is correct.

6 0
2 years ago
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