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prisoha [69]
3 years ago
7

Multpily 10/-8 x 2/7 x (-9)

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer: 72/35

Step-by-step explanation:

10/-8 = -8/10 = -.8

-0.8*(2/7)*-9= about 2.06.(72/35)

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Solve the right triangle​
grandymaker [24]

Answer:

HJ = 5.20

HI = 3

angle J = 30 degrees

Step-by-step explanation:

sin 60 = HJ/6

HJ = 5.20

cos 60 = HI/6

HI = 3

angle J = 90-60 = 30 degrees

4 0
2 years ago
Solve for all values of y<br> in simplest form.<br><br> ∣y−12∣=16
Reil [10]

Answer:

y=-4; y=28

Step-by-step explanation:

The way I like to think about it, with absolute value meaning the distance is

"find which number are 16 apart from 12". Which means 28 (to the right) or -4 (to the left).

More formally, applying the definition of absolute value,

|y-12|=16 \leftrightarrow y-12=\pm16\\y-12=-16 \rightarrow y=-4\\y-12=+16 \rightarrow y=28

5 0
1 year ago
Algebraically find the x and y intercept of y=-2x+6
snow_lady [41]
Oh gosh gosh i hope you have a good day bye bye merry christmas merry christmas happy birthday happy merry merry thanksgiving
6 0
3 years ago
A person standing close to the edge on top of a 24-foot building throws a ball vertically upward. The quadratic function h(t)=−1
Nutka1998 [239]

Answer:

a) maximum height is 156.25 ft

b) 6 seconds

Step-by-step explanation:

a) The maximum height can be found by finding the y-coordinate of the vertex. The vertex is the highest point in a parabola opened downward.

I start with by finding the t-coordinate of the vertex.

The t-coordinate of the vertex is \frac{-b}{2a} where the expression -16t^2+92t+24 will need to be compared to at^2+bt+c.

We see that a=-16,b=92,c=24.

So the t-coordinate of the vertex is \frac{-b}{2a}=\frac{-92}{2(-16)}=\frac{-92}{-32}=\frac{23}{8}.

We can find the h, the height, that corresponds to this t by using the equation h=-16t^2+92t+24 where t=\frac{23}{8}.

So inserting 23/8 for t.

-16(23/8)^2+92(23/8)+24

Plugging into calculator gives you 625/4.

So the maximum height is 625/4 or 156.25.

b) Let's find how long it takes the ball to hit the ground. If the ball is on the ground, then the distance between the ball and the ground is 0.  So we are looking to solve h(t)=0 for t.

So this is equation we are solving for t:

-16t^2+92t+24=0

These numbers are big but since all the terms have a common factor we can make them slightly smaller.

That is, we are going to divide both sides by -4 and see

4t^2-23t-6=0

It looks like it could be possible to factor.

a=4

b=-23

c=-6

We need to find two numbers that multiply to be ac and add up to be b.

a*c=4(-6)=-24

b=-23

So -24=-24*1 and -23=-24+1.

We are going to replace -23t with -24t+1t giving up something that should be factorable by grouping.

4t^2-23t-6=0

4t^2-24t+1t-6=0

Group the first 2 together and group the last two together:

(4t^2-24t)+(1t-6)=0

Factor what you can from each pair:

4t(t-6)+1(t-6)=0

Now each term has a common factor of (t-6) so factor that out giving you:

(t-6)(4t+1)=0

Set both factors equal to 0 giving you

t-6=0              or               4t+1=0

  t=6               or               4t  =-1

  t=6               or                 t=-1/4

So it hit the ground in 6 seconds.

8 0
3 years ago
Two angle measures of a quadrilateral are 34° and 66°. What could the measure of the other two angles be?
elena-s [515]
The correct answer is c 150 and 110

7 0
2 years ago
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