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fredd [130]
2 years ago
8

What is the quotient of the given expression?

Mathematics
1 answer:
aivan3 [116]2 years ago
6 0

Answer:3x^3 – 5x^2 + 10x – 3) – (3x. Dividing the new leading term, –6x2, by the divisor's leading term, 3x, I get –2x, so I put this on top: (–6x^2) ÷ (3x) = –2x, which goes. Then I multiply –2x by 3x + 1 to get –6x2 – 2x ...

Step-by-step explanation:

3x^3 – 5x^2 + 10x – 3) – (3x. Dividing the new leading term, –6x2, by the divisor's leading term, 3x, I get –2x, so I put this on top: (–6x^2) ÷ (3x) = –2x, which goes. Then I multiply –2x by 3x + 1 to get –6x2 – 2x ...

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Guys plz help me answer this!!!
ddd [48]

Answer:           number 2

cuz its the only one that makes sense

5 0
2 years ago
It was recently estimated that domestic vehicles outnumber foreign vehicles by about seven to three. If there are 3100 vehicles
notka56 [123]

Answer:

feQEf

Step-by-step explanation:

FqwDXZ

3 0
2 years ago
Which expression shows the result of applying the distributive property to  12(5y+4) ?
brilliants [131]
<span>12(5y+4)
= 12(5y) + 12(4)
= 60y + 48

hope it helps</span>
6 0
3 years ago
PLEASE HELP<br><br> x = ___ units
Shkiper50 [21]

Answer:

x = <u>16</u> units

Step-by-step explanation:

∆ABC is a 45-45-90 triangle, and ∆BCD is a 30-60-90 triangle.

If side opposite of 90° [∆] = x, side opposite of 45° [∆] = x / √2 = x √ 2 / 2.

Given side AC is opposite of 90° [∆ABC] = 32 √ 2, side opposite of 45° [∆ABC] = 32 √ 2 / √ 2 = 32 which is AB or BC.

Since side BC is part of BCD.

Side opposite of 90° [∆BCD] = BC = 32.

Since x is opposite of 30° [∆BCD].

x = Side opposite of 90° [∆BCD] / 2 = 32 / 2 = 16.

8 0
2 years ago
You plant a rectangular rose garden along the side of your garage. You enclose 3 sides of the garden with 40 feet of fencing. Th
solmaris [256]

Let's assume

length of rectangle =L

width of rectangle =W

You enclose 3 sides of the garden with 40 feet of fencing

so, we get

L+2W=40

now, we can solve for L

L=40-2W

we know that

area of rectangle is

A=L*W

100=L*W

now, we can plug

100=(40-2W)*W

now, we can solve for W

-2W^2+40W-100=0

we can use quadratic formula

W=\frac{-40+\sqrt{40^2-4\left(-2\right)\left(-100\right)}}{2\left(-2\right)}

W=\frac{-40-\sqrt{40^2-4\left(-2\right)\left(-100\right)}}{2\left(-2\right)}

we can take anyone value ..because both are giving positive value

first dimensions:

W=2.929

now, we can find L

L=40-2*2.929

L=34.142

so, length is 34.142feet

width is 2.929 feet

Second dimensions:

W=17.071

now, we can find L

L=40-2*17.071

L=5.858

so, length is 5.858feet

width is 17.071 feet



6 0
3 years ago
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