You can set up a system of equations for this problem. x= number of coach tickets and y = number of first class tickets.
$210x + $1200y = $10,230 (cost of coach ticket plus cost of first class tickets is total budget)
x + y = 11 (number of coach tickets plus number of first class tickets is total number of people)
Solve the second equation for y to get y = 11 - x, then plug that into the first equation and solve for x:
$210x + $1200(11 - x) = $10,230
$210x + $13,200 - $1200x = $10,230
-$990x + $13,200 = $10,230
-$990x = $2,970
x = 3
Sarah bought x = 3 coach tickets. Plug that into the second equation and solve for y:
3 + y = 11
y = 8
Sarah bought y = 8 first class tickets.
Find the slope and use one point to write the equation of a line (we’ll be using point-slope form). The slope is:
(3 - (-2) ) / (4 - (-1) ) = 1. Plug it into point slope form, y - y1 = m(x - x1), and we get y - 3 = 1(x - 4). If we want to get slope-intercept, distribute the 1, and solve for y: y = x - 1.
10g^3 + 12g^2 - 15g - 18 = 2g^2(5g + 6) - 3(5g + 6) = (2g^2 - 3)(5g + 6)
Y+4=3/2(x+2)
y+4=3/2x+3
y=3/2x-1
y = 3/2x - 1
Answer:
m = 2k/v²
Step-by-step explanation:
I think you mean solve for m, not k
Multiply both sides of the equation by 2
2 * 1/2 *(mv²) = 2 * k
Rewrite the expression.
1*(mv²) = 2*k
Multiply mv² by 1
mv² = 2*k
Divide each term by v² and simplify
mv²/v² = 2k/v²
mv²/v² cancel out and you get
m = 2k/v²
