What is the equivlalent expression of 10 plus 10 plus 10

A survey in Men’s Health magazine reported that 39% of cardiologists said that they took vitamin E supplements. To see if this i

zzz [600]

Answer:

$z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615$

The p value for this case would be:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

Step-by-step explanation:

Information given

n=100 represent the random sample taken

X=36 represent the number of people that take E supplement

$\hat p=\frac{36}{100}=0.36$ estimated proportion of people who take R supplement

$p_o=0.39$ is the value that we want to test

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true proportion is equatl to 0.39 or not, the system of hypothesis are.:

Null hypothesis: $p=0.39$

Alternative hypothesis: $p \neq 0.39$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info we got:

$z=\frac{0.36 -0.39}{\sqrt{\frac{0.39(1-0.39)}{100}}}=-0.615$

The p value for this case would be:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion is not different from 0.39

8 0

3 years ago

Solve the equation 4p+9+(-7p)+2=

mr_godi [17]

4p+9-7p+2=
group like terms
4p-7p+9+2
addd like terms
-3p+11
that is simplified form

6 0

3 years ago

The population of Adamsville grew from 7,000 to 12,000 in 5 years. Assuming uninhibited exponential growth, what is the expected

mr Goodwill [35]

We have that if we assume standard exponential growth, the equation of the population will be: $7000*e^{kt}$ if we start counting from the moment that the population was 7000. We are given that 7000* $e^{5k}$ =12000, namely that P(5)=12000 and we need to find $7000e^{(5+5)k}=7000e^{10k}$ . Since e^(10k)=e^(5k)*e^(5k), and since we can solve for e^(5k) from P(5), we have:
e^(5k)=12000/7000 and we can calculate P(10). P(10)=7000 $\frac{12000^2}{7000^2}$ = 20571 people.

3 0

3 years ago

Which of the following could Not be the side length of a right triangle?

ArbitrLikvidat [17]

Answer:

I think ITS B

Step-by-step explanation:

Hope this helped

-BB

8 0

3 years ago

Read 2 more answers

Lisa sale de su casa y recorre su ruta a una velocidad de 1.15m/s, que ten

Gnoma [55]

No entiendo española

8 0

3 years ago

What is the equivlalent expression of 10 plus 10 plus 10​

What is the equivlalent expression of 10 plus 10 plus 10