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3 years ago

Explain how to graph the in inequality 8>y

Mathematics

1 answer:

insens350 [35]3 years ago

8 0

Answer:

How to Graph a Linear Inequality

First, graph the "equals" line, then shade in the correct area.

There are three steps:

1.) Rearrange the equation so "y" is on the left and everything else on the right.

2.) Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

4.) Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).

Hope This Helps! Have A Nice Day!!

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Lesley and Enid left their waitress a 15% tip.

jok3333 [9.3K]

Answer: $68.37

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7 0

3 years ago

-15 + 12x = 5x + 7 -3x SOLVE FOR X

Natali [406]

Answer: $x=\frac{11}{5}$

Simplify both sides of the equation

$-15+12x=5x+7+-3x$

$12x-15=(5x+-3x)+(7)$ (Combine Like Terms)

$12x-15=2x+7$

Subtract 2x from both sides

$12x-15-2x=2x+7-2x\\10x-15=7$

Divide both sides by 10

$\frac{10x}{10} =\frac{22}{10}$

$x=\frac{11}{5}$

6 0

3 years ago

Read 2 more answers

Y = 3x - 1

lubasha [3.4K]

Answer:

no solution.

Step-by-step explanation:

given that, y = 3x-1

so,

in equation, 3x-y = 9

putting the value of y here,

3x-(3x-1) = 9

3x-3x+1 = 9

3x and 3x is cancelled.

hence, no solution

6 0

3 years ago

If E(X)=100, E(Y)=120, E(Z) = 130, Var(X) = 9, Var(Y) = 16, Var(Z) = 25, Cov(X, Y)= - 10 Cov(X,Z) = 12, and Cov(Y,Z) = 14, then

vredina [299]

Answer:

(1) -0.833

(2) 0.80

(3) 0.70

(4) 390

(5) 90

(7) 48

Step-by-step explanation:

Given:

E (X) = 100, E (Y) = 120, E (Z) = 130

Var (X) = 9, Var (Y) = 16, Var (Z) = 25

Cov (X, Y) = -10, Cov (X, Z) = 12, Cov (Y, Z) = 14

The formulas used for correlation is:

$Corr (A, B) = \frac{Cov (A, B)}{\sqrt{Var (A)\times Var(B)}} \\$

(1)

Compute the value of Corr (X, Y)-

$Corr (X, Y) = \frac{Cov (X, Y)}{\sqrt{Var (X)\times Var(Y)}} \\=\frac{-10}{\sqrt{9\times16}} \\=-0.833$

(2)

Compute the value of Corr (X, Z)-

$Corr (X, Z) = \frac{Cov (X, Z)}{\sqrt{Var (X)\times Var(Z)}} \\=\frac{12}{\sqrt{9\times25}} \\=0.80$

(3)

Compute the value of Corr (Y, Z)-

$Corr (Y, Z) = \frac{Cov (Y, Z)}{\sqrt{Var (Y)\times Var(Z)}} \\=\frac{14}{\sqrt{16\times25}} \\=0.70$

(4)

Compute the value of E (3X+4Y-3Z)-

$E(3X+4Y-3Z)=3E(X)+4E(Y)-3E(Z)\\=(3\times100)+(4\times120)-(3\times130)\\=390$

(5)

Compute the value of Var (3X-3Z)-

$Var (3X-3Z)=[(3)^{2}\times Var(X)]+[(-3)^{2}\times Var (Z)]+(2\times3\times-3\times Cov(X, Z)]\\=(9\times9)+(9\times25)-(18\times12)\\=90$

(6)

Compute the value of Var (3X+4Y-3Z)-

$Var (3X+4Y-3Z)=[(3)^{2}\times Var(X)]+[(4)^{2}\times Var(Y)]+[(-3)^{2}\times Var (Z)]+[(2\times3\times4\times Cov(X, Y)]+[(2\times3\times-3\times Cov(X, Z)]+[(2\times4\times-3\times Cov(Y, Z)]\\=(9\times9)+(16\times16)+(9\times25)+(24\times-10)-(18\times12)-(24\times14)\\=-230$