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Alisiya [41]
3 years ago
14

ricardo has 2 cases of video games with the same number of games in each case. he give 4 games to his brothers.ricardo has 10 ga

mes left .how many games where in each case
Mathematics
1 answer:
BARSIC [14]3 years ago
8 0
His brothers have 4 games
He had 10 games
So in total there are 14 games
And if there are 2 cases and each one had the same amount, then in each one there would be 14÷2=7

In each case, there are 7 games.
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Oneta writes an algebraic expression with three terms. The y-term has a coefficient of -3, and the x-term has a coefficient of 1
WINSTONCH [101]

Answer:

Step-by-step explanation:

If X + 3y + 7 is squared by 3y then your answer should be X + 3y sq. + 7 = 10x sq.

6 0
3 years ago
the length of diagonal of a rectangular field is 23.7 m and one of its sides is 18.8 m. find the perimeter of the field.​
katen-ka-za [31]

Answer:

Approximately 66.4 Meters

Step-by-step explanation:

So we have a rectangle with a width of 18.8 meters and a diagonal with 23.7 meters. To find the perimeter, we need to find the length first. Since a rectangle has four right angles, we can use the Pythagorean Theorem, where the diagonal is the hypotenuse.

a^2+b^2=c^2

Plug in 18.8 for either <em>a </em>or <em>b. </em>Plug in the diagonal 23.7 for <em>c. </em>

<em />(18.8)^2+b^2=23.7^2\\b^2=23.7^2-18.8^2\\b=\sqrt{23.7^2-18.8^2} \\b\approx14.4 \text{ meters}

Therefore, the length is 14.4 meters. Now, find the perimeter:

P=2l+2w\\P=2(14.4)+2(18.8)\\P=66.4\text{ meters}

7 0
3 years ago
Why can you NOT combine 3x and 5x^2 ?
diamong [38]
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I hope that helps.
7 0
4 years ago
What is 1m + 3/4 this too hard
TiliK225 [7]

Answer:

m = - 3 / 4

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4 0
2 years ago
Read 2 more answers
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
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