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Mariana [72]
2 years ago
6

The water has been on the stove y=9.5x+62.1 after how many minutes will the tempature be 138.1 F

Mathematics
1 answer:
kotegsom [21]2 years ago
4 0

Answer:

After 8 minutes will the temperature be 138.1 F

Step-by-step explanation:

Given that:

The water has been on the stove y=9.5x+62.1      .....[1]

where

y represents the temperature in Fahrenheit(F)

x represents the time in minutes.

We have to find after how many minutes will the temperature be 138.1 F.

⇒y = 138.1 F

Substitute the given value in [1] to solve for x;

138.1=9.5x+62.1

Subtract 62.1 from both sides we get;

76=9.5x

Divide both sides by 9.5 we get;

8 = x

or

x = 8 minutes.

Therefore, after 8 minutes will the temperature be 138.1 F

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To find slope subtract the two points in the coordinate (y). We have 8 and 4 so subtract those two. You get 8-4=4. Now start from the same coordinate expect this time subtract (x). Which is 9-3=6. You have 4/6 simplify and you get 2/3. Your slope is 2/3. Hope this helps
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2 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

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2 years ago
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Answer:

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