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Alecsey [184]
3 years ago
6

The water at the end of a pier was 28 meters deep at midnight. As the tide came in, the water depth increased at a rate of 0.012

meters per minute. Which equation can be solved to find t, the time in minutes it took the water depth to reach 30 meters?
(t/0.012) - 28 = 30
0.012t + 28 = 30
(t/0.012) + 28 = 30
0.012t – 28 = 30
Mathematics
1 answer:
Nastasia [14]3 years ago
4 0

Answer:

  0.012t + 28 = 30

Step-by-step explanation:

The depth starts at 28 meters. The amount of increase in t minutes will be 0.012t, so the total depth after t minutes is ...

  0.012t +28

We want to find when that is equal to 30, so the appropriate equation is ...

  0.012t +28 = 30

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Answer:

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c) Unusual

Step-by-step explanation:

We have a population proportion p=0.36 and we are taking a sample of size n=2500. This can be modeled as binomial sampling.

For this sampling distribution, we have a mean and STD that can be calculated as:

\mu_s=n\cdot p=2500\cdot0.36=900\\\\\sigma_s=\sqrt{n\cdot p(1-p)}=\sqrt{2500*0.36*0.64)}=\sqrt{576}=24

b) A value of 840 is a very unusual as is more than 2 standard deviations from the expected value of 900 (more exactly, at 2.5 standard deviations). Approximately 2% of the values are below 2 standars deviations from the mean.

Having 840 or less televisions tuned to "Eyewitness News" would have a probability of P=0.00621.

c) A value of 945 would be also unusual, but not as unusual as 840, as is between 1 and 2 standard deviation from the expected value.

Having 945 or more televisions tuned to "Eyewitness News" would have a probability of P=0.0304.

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What is the arc length of an arc with radius 10 in and central angle 60 degrees ? Show your work.
emmasim [6.3K]

Answer:

\huge \boxed{ \boxed{ \red{{s \approx \: 10.47}}}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • geometry
  • PEMDAS
<h3>tips and formulas:</h3>
  • s =  \frac{\pi {r} \theta}{180}
<h3>given:</h3>
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<h3>let's solve:</h3>
  1. \sf sustitute \: the \: value s \: of \:  \theta \: and \: r :  \\  =\frac{\pi \times 10 \times 60}{180}
  2. \sf rediuce \: 60 :  \\  =\frac{\pi \times 10 \times  \cancel{60}  \: ^{1} }{ \cancel{180}  \:  \:^{3} }  \\  =\frac{\pi \times 10}{3}
  3. \sf use \: 3.14 \: for \: \pi :  \\ = \frac{3.14 \times 10}{3}
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