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dusya [7]
3 years ago
10

NEED HELP!!!

Chemistry
1 answer:
Anit [1.1K]3 years ago
3 0

Answer:

energy is released in the reaction.

Explanation:

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Thunder and lightning make atoms true or false
guajiro [1.7K]
False, atoms can not be created that way
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3 years ago
Choose the best tool for each scenario.
Mama L [17]

Answer:

a) Graph

b) Weight balance or gas syringe  or upside-down measuring cylinder

Explanation:

a) Identifying a trend in temperature change over time - The best tool for this scenario is to represents the temperature daily, weekly, monthly or annually on graph to interpret the fluctuation in temperature owing to local seasonal changes and weather conditions

b) Measuring the mass of a product of a chemical reaction - If the product is solid or liquid then the balance is used to measure the mass. If the product is a gas, then  gas syringe  or upside-down measuring cylinder is used.

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3 years ago
What happens as a result of photoelectric effect
natka813 [3]

Electrons are emitted from the surface of a metal in photoelectric effect.

<h3>What is the photoelectric effect?</h3>

The photoelectric effect is the emission of electron from the surface of a metal when light is shone on the surface..

For electrons to be emitted, the light must have a certain frequency known as threshhold frequency.

Therefore, electrons are emitted from the surface of a metal in photoelectric effect.

Learn more about photoelectric effect at: brainly.com/question/21320305

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5 0
2 years ago
The reaction is proceeding at a rate of 0.0080 Ms-1 in 50.0 mL of solution in a system with unknown concentrations of A and B. W
Leokris [45]

Answer:

0.0010 mol·L⁻¹s⁻¹  

Explanation:

Assume the rate law is  

rate = k[A][B]²

If you are comparing two rates,

\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \dfrac{k_{2}\text{[A]}_2[\text{B]}_{2}^{2}}{k_{1}\text{[A]}_1[\text{B]}_{1}^{2}}= \left (\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}}\right ) \left (\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}\right )^{2}

You are cutting each concentration in half, so

\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}} = \dfrac{1}{2}\text{ and }\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}= \dfrac{1}{2}

Then,

\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \left (\dfrac{1}{2}\right ) \left (\dfrac{1}{2}\right )^{2} = \dfrac{1}{2}\times\dfrac{1}{4} = \dfrac{1}{8}\\\\\text{rate}_{2} = \dfrac{1}{8}\times \text{rate}_{1}= \dfrac{1}{8}\times \text{0.0080 mol$\cdot$L$^{-1}$s$^{-1}$} = \textbf{0.0010 mol$\cdot$L$^{-1}$s$^{-1}$}\\\\\text{The new rate is $\large \boxed{\textbf{0.0010 mol$\cdot$L$^\mathbf{{-1}}$s$^{\mathbf{-1}}$}}$}

8 0
3 years ago
How many grams does 1.0 liter of motor the density of motor oil is 0.80g / mL
balandron [24]
I think the answer is 1.25 grams actually i think i’m wrong
5 0
3 years ago
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