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not every expirement has control
Phosphorus, copper, carbon monoxide, hydro cyanic acid, nitrates, potassium chlorate, and aniline are some of the examples of poison that can be identified by a color test according to forensic pathology.
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Answer: Diagram of the nuclear composition, electron configuration, chemical data, and valence orbitals of an atom of boron-11 (atomic number: 5), the most common isotope of the element boron. The nucleus consists of 5 protons (red) and 6 neutrons (orange). Five electrons (white) occupy available electron shells (rings).
Explanation:
Firstly need to determine the empirical formula of the hydrocarbon. Empirical formula is the simplest whole number ratio of components of the compound. Molecular formula is the actual composition of the components in the compound.
percentage of C - 82.66%
percentage of H - (100-82.66) = 17.34 %
in 100 g of compound ;
mass of C - 82.66 g
mass of H - 17.34 g
C H
mass in 100 g 82.66 g 17.34 g
molar mass 12 g/mol 1 g/mol
number of moles 6.88 mol 17.34 mol
(mass/molar mass)
divide the number of moles by least number of moles (6.88 mol)
6.88 mol/6.88 17.34/6.88
1 2.52
multiply these by 2 to get a whole number
C - 1x 2 = 2
H - 2.52 x 2 = 5.04
round off to nearest whole number
C - 2
H - 5
ratio of C to H is 2:5
empirical formula - C₂H₅
empirical formula mass = 12 g/mol x 2 + 5 * 1 g/mol = 29 g
next have to find how many empirical units are there in the molecular unit
molecular unit mass = 58.12 g
empirical unit = 29 g
then number of empirical units = 58.12 / 29 = 2
rounded off , number of empirical units = 2
(C₂H₅) * 2 units
molecular formula = C₄H₁₀
Explanation:
Answer:
lets set the ratio -A/HA as R:
pH = pKa + log(R,10) => pKa + log10(R)
pH = 5.5
pKa = 4.76
R => 10^(pH - 4.76)
10^(pH - 4.76) => 5.4954
Given R (-A/HA) a number bigger than 1, then the concentration of -A is bigger than HA
Explanation:
